Question

At an instant when a soccer ball is in contact with the foot of the player kicking it, the horizontal or x component of the ball's acceleration is 800 m/s^2 and the vertical or y component of its acceleration is 880 m/s^2. The ball's mass is 0.37 kg. What is the magnitude of the net force acting on the soccer ball at this instant?

Answer 1

Answer:440.03 N

Explanation:

Given

horizontal component of acceleration $(a_x)=800 m/s^2$

vertical component of acceleration $(a_y)=880 m/s^2$

mass of ball =0.37 kg

Force in horizontal direction$=m\times a_x=0.37\times 800=296 N$

Force in vertical direction $=m\times a_y=0.37\times 880=325.6 N$

Therefore net force is

$F=F_x+F_y$

$|F|=\sqrt{296^2+325.6^2}$

|F|=440.03 N