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4 years ago

how do you relate the equations for kinetic and potential energy to illustrate the law of conservation of energy?

1 answer:

3 0

The conservation of energy is a principle stating that energy cannot be created or destroyed but can be altered from one form to another. With that said. Potential Energy would be like a Rubber band, just sitting there, nothing will happen, however when one picks it up, and stretches it between the fingers, and then lets go of it, Potential energy from the still rubber band becomes Kinetic energy as it flies through the air.
Kinetic meaning motion. Potential meaning not moving however it has the potential for moving as I described above. Hope this helps.

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A fireman is standing on top of a building 19 m high, holding a firehose 1 m above the top of the building. She finds that if sh

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Answer:

A 2 d vector model

The acceleration function is -9.8 m/s2 which is gravity

Initial velocity on the Y axis is 0, on the X axis is 12 m/s

Inital position is 20 mts above the ground.

It takes the water 1.01 seconds to reach the other building.

THe distace from one building to the other is 12.11 meters.

Explanation:

In order to solve this you just need to carefully read the problem and the data you are given, and use the formula for height in free fall:

$h=\frac{1}{2} g*t^{2}$

So first the data, we know that the water is coming out at a height of 20 meters since the building is 19 meters tall and the fireman is holding the firehose 1 meter above it, and the water is hitting the second building at a height of 15 meters, that means that the water is travelin -5meters.

Gravity as it doesn´t say otherwise would be 9.8m/s2 since that is gravity on earth, and water is leaving the firehose at 12m/s horizontally.

We can calculate the time by using the height formula fro free fall:

$h=\frac{1}{2} g*t^{2}\\5=\frac{1}{2} 9.81*t^{2}\\t^{2}= \frac{10}{9.8} \\t^{2}=1.0193\\t=1.009 seconds$

So it takes 1.009 seconds for the water to frop from 20 to 15 meters, as the horizontal velocity remains the same we just multiply it by the time and we get the horizontal distance between the two buildings and that would be:

12.11 meters.

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