Answer:
The amount of work that must be done to compress the gas 11 times less than its initial pressure is 909.091 J
Explanation:
The given variables are
Work done = 550 J
Volume change = V₂ - V₁ = -0.5V₁
Thus the product of pressure and volume change = work done by gas, thus
P × -0.5V₁ = 500 J
Hence -PV₁ = 1000 J
also P₁/V₁ = P₂/V₂ but V₂ = 0.5V₁ Therefore P₁/V₁ = P₂/0.5V₁ or P₁ = 2P₂
Also to compress the gas by a factor of 11 we have
P (V₂ - V₁) = P×(V₁/11 -V₁) = P(11V₁ - V₁)/11 = P×-10V₁/11 = -PV₁×10/11 = 1000 J ×10/11 = 909.091 J of work
A compound Machine is 2 machines that work together in order to make a task easier.
P1 and P2 are the pressures, and V1 and V2 are the volumes. So you take the first pressure and volume you are given and place them into the equation P1V1 so the first part of the equation would be 101000*0.5 = P2V2. You then rearrange the equation to find what you want, in this instance you would do 50500/0.25 = P2... therefore P2 = 2020000Pa or 2.02*10^6Pa
Explanation:
We have,
Spring constant of the spring, k = 165 N/m
Mass, m = 2 kg
It is required to find the period of the mass-spring system. For the spring mass system, the period is given by :

The frequency of vibration is reciprocal of its time period. So,

So, the period of the mass-spring system is 0.69 s and frequency is 1.44 Hz.