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son4ous [18]
3 years ago
12

A beach ball is rolling in a straight line toward you at a speed of 0.5 m/s. Its

Physics
1 answer:
Rudiy273 years ago
3 0

Answer:

.5 kg

Explanation:

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When electrons absorb energy they are able to
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B. Move from their ground states up to excited states

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A 10 kg block rests on a 30o inclined plane. The block is attached to a bucket by pulley system depicted below. The mass in the
DiKsa [7]

Answer:

a). M = 20.392 kg

b). am = 0.56 m/s^2 (block),  aM = 0.28 m/s^2 (bucket)

Explanation:

a). We got  N = mg cos θ,

                  f = $\mu_s N$

                    = $\mu_s mg \cos \theta$

If the block is ready to slide,

T = mg sin θ + f

T = mg sin θ + $\mu_s mg \cos \theta$   .....(i)

2T = Mg ..........(ii)

Putting (ii) in (i), we get

$\frac{Mg}{2}=mg \sin \theta + \mu_s mg \sin \theta$

$M=2(m \sin \theta + \mu_s mg \cos \theta)$

$M=2 \times 10 \times (\sin 30^\circ+0.6 \cos 30^\circ)$

M = 20.392 kg

b). $(h-x_m)+(h-x_M)+(h'+x_M)=l$  .............(iii)

   Here, l = total string length

Differentiating equation (iii) double time w.r.t t, l, h and h' are constants, so

$-\ddot{x}-2\ddot x_M=0$

$\ddot x_M=\frac{\ddot x_m}{2}$

$a_M=\frac{a_m}{2}$   .....................(iv)

We got,   N = mg cos  θ

                $f_K=\mu_K mg \cos \theta$

∴ $T-(mg \sin \theta + f_K) = ma_m$

  $T-(mg \sin \theta + \mu_K mg \cos \theta) = ma_m$  ................(v)

Mg - 2T = Ma_M

$Mg-Ma_M=2T$

$Mg-\frac{Ma_M}{2} = 2T$    (from equation (iv))

$\frac{Mg}{2}-\frac{Ma_M}{4}=T$   .....................(vi)

Putting (vi) in equation (v),

$\frac{Mg}{2}-\frac{Ma_M}{4}-mf \sin \theta-\mu_K mg \cos \theta = ma_m$

$\frac{g\left[\frac{M}{2}-m \sin \theta-\mu_K m \cos \theta\right]}{(\frac{M}{4}+m)}=a_m$

$\frac{9.8\left[\frac{20.392}{2}-10(\sin 30+0.5 \cos 30)\right]}{(\frac{20.392}{4}+10)}=a_m$

$a_m= 0.56 \ m/s^2$

Using equation (iv), we get,

a_M= 0.28 \ m/s^2

6 0
3 years ago
A sound wave traveling eastward through air
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1 - Vibrate east and west

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A bicycle generator rotates at 154 rads/s, producing an 16.5 V peak emf. It has a 1.00 by 3.00 cm rectangular coil in a 0.68 T f
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Answer:

525.2

Explanation:

w = 154 rad/s, e0 = 16.5 V, A = 1 x 3 = 3 cm^2 = 3 x 10^-4 m^2, B = 0.68 T

Let the number of turns be N.

By use of law of electromagnetic induction

e0 = N B A w

16.5 = N x 0.68 x 3 x 10^-4 x 154

N = 525.2

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What will happen to a waves frequency if it’s speed increases and it’s wavelength remains the same?
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Answer:Actually the wavelength is proportional to its speed and frequency. therefore the wavelength has no affect on the speed or frequency its the other way around.

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