Answer:
The air pressure in the ears increases
The volume of air in the ears increases
The change in volume causes discomfort
It takes time for the ears to dispell excess air past the ear drum.
Explanation:
As the plane engages in a steep incline into the atmosphere, the outside atmospheric pressure decreases with altitude. The air pressure in the ear, therefore, become greater than atmospheric pressure. The air volume in the ear therefore grows and pushes on the ear causing discomfort. As the air in the cabin pressurizes the discomfort eases away as pressure equalization is restored relative to the ear.
Love the toradora pfp, also the answer to your question is...
answer: from newtons second law of motion,
F=ma hence,
F=20N
m=5kg so,
20=5×a
a=4m/s^2
a.NH₃+HCl⇒NH₄Cl
b.volume HCl=150 ml
c. pH=4.82
<h3>Further explanation</h3>
Reaction
NH₃+HCl⇒NH₄Cl
The equivalence point⇒mol NH₃=HCl
Titration formula :
M₁V₁n₁=M₂V₂n₂(n=acid base valence, NH₃=HCl=1)
mol NH₃

mol HCl=75 mlmol

Volume total :

mol NH₄Cl=mol NH₃=75 mlmol=0.075 mol

Dissociation of NH₄Cl at water to find [H₃O⁺]

ICE at equilibrium :
0.41-x x x
Ka(Kw:Kb)= 10⁻¹⁴ : 1.8.10⁻⁵=5.6.10⁻¹⁰

[H₃O⁺]=x :

pH=-log[H₃O⁺]

Answer:
<em>Most fire extinguishers work by separating the fuel from the oxygen. The oxygen comes from the air. It is the same oxygen we breathe. Since the oxygen has to be in contact with the fuel, if you can coat the fuel with something that keeps the oxygen away, the fire will go </em><em>out.</em><em> </em><em>S</em><em>ome </em><em>ways </em><em>of </em><em>using </em><em>fire </em><em>extinguisher </em><em>are:</em>
- <em> Water extinguishers work mainly by cooling (removing heat), but a dense spray of water droplets also helps to cut off oxygen. </em>
- <em> Dry powder extinguishers soak up heat, melt on the fuel, and cut off oxygen, but they also neutralize the </em><em>fuel</em><em> (cutting it off from the </em><em>fire)</em><em> </em><em>.</em>
Explanation:
I hope it was helpful...
Answer:
half-life=T= 36.9 years
Explanation:
As we know that
N
(
t
)
=
N
(
0
)
⋅
0.5
^(t/
T
)
N
(
0
)
=the number of atoms you start with=20 gram
and N
(
t
)= the number of atoms left=0.625 grams
after a certain time=t=184.5 years
T=half life of a nuclide=?
Putting value in above equation we get
half-life=T= 36.9 years
.