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3 years ago

If you add enzyme to a solution containing only the product(s) of a reaction, would you expect any substrate to form?

Chemistry

1 answer:

Masteriza [31]3 years ago

8 0

Answer:

Explanation:

Provided the reaction that leads to the formation of the products can proceed in both forward and backward directions, the correct answer would be yes because the reaction will proceed backward until equilibrium is reached.

For a reaction that can proceed both forward and backward, the addition of a catalyst increases the rate of reaction in both directions based on the fact that a catalyst cannot alter the equilibrium of a reaction.

Hence, if an enzyme is added to the product of a reaction that has the potential to proceed in both forward and reverse reactions, a substrate would be expected to form because the reaction will proceed backward until an equilibrium is reached.

The correct option is e.

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tigry1 [53]

Answer:

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Explanation:

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3 years ago

Calculate the partial pressure of each gas and the total pressure if the temperature of the gas is 15 ∘C.

umka2103 [35]

Answer:

P(oxygen gas) = 3.75atm

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Explanation:

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3 years ago

Look at the equation CO2 + H2 = CO + H20.

sergejj [24]

Answer:

CO is considered as a product.

Explanation:

A general chemical equation for a combination reaction follows:

To write a chemical equation, we must follow some of the rules:

The reactants must be written on the left side of the direction arrow.

A '+' sign is written between the reactants, when more than one reactants are present.

An arrow is added after all the reactants are written in the direction where reaction is taking place. Here, the reaction is taking place in forward direction.

The products must be written on the right side of the direction arrow.

A '+' sign is written between the products, when more than one products are present.

For the given chemical equation:

are the reactants in the reaction and are the products in the reaction.

Hence, CO is considered as a product.

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3 years ago

The CNO cycle produces energy in which of the following?

d1i1m1o1n [39]

Stars on the main sequence fuse hydrogen into helium via a six-stage sequence of reactions

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3 years ago

The equilibrium constant for the dissolution of silver chloride (AgCl(s) Ag+(aq) + Cl–(aq)) has a value of 1.79 × 10–10. Which s

ryzh [129]

"Silver chloride is essentially insoluble in water" this statement is true for the equilibrium constant for the dissolution of silver chloride.

Option: b

Explanation:

As silver chloride is essentially insoluble in water but also show sparing solubility, its reason is explained through Fajan's rule. Therefore when AgCl added in water, equilibrium take place between undissolved and dissolved ions. While solubility product constant $\left(\boldsymbol{K}_{s p}\right)$ for silver chloride is determined by equilibrium concentrations of dissolved ions. But solubility may vary also at different temperatures. Complete solubility is possible in ammonia solution as it form stable complex as water is not good ligand for Ag+.

To calculate $\left(\boldsymbol{K}_{s p}\right)$ firstly molarity of ions are needed to be found with formula: $\text { Molarity of ions }=\frac{\text { number of moles of solute }}{\text { Volume of solution in litres }}$

Then at equilibrium cations and anions concentration is considered same hence:

$\left[\mathbf{A} \mathbf{g}^{+}\right]=[\mathbf{C} \mathbf{I}]=\text { molarity of ions }$

Hence from above data $\left(\boldsymbol{K}_{s p}\right)$ can be calculated by: $\left(\boldsymbol{K}_{s p}\right)$ = $\left[\mathbf{A} \mathbf{g}^{+}\right] \cdot[\mathbf{C} \mathbf{I}]$

6 0

3 years ago