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4 years ago

Your heating system is 60% efficient. If it consumes 12,052 kWh of energy to heat

Physics

1 answer:

Mandarinka [93]4 years ago

7 0

Answer:

E = 7231.2 [kWh]

Explanation:

All systems that produce work in the mechanical form of movement or heat, they have an efficiency that depends on the construction technology, ideally in each of these equipments is that their efficiencies are as high as possible, that is, its efficiency is close to 100%. For this case we have an equipment with 60% efficiency, this heating system is characterized since of the 12,052 kWh, it uses 60% of this value only to heat the house, the rest of energy is known as lost.

E = 12,052 * (60/100)

E = 7231.2 [kWh]

This amount of energy 7231.2 [kWh] is used for heating purposes.

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10. A kicked soccer ball has an initial velocity of 30 m/s at an angle of 42° above the horizontal, level

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Answer:

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Explanation:

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3 years ago

Si el sonido no atraviesa las paredes entonces, ¿por qué se escuchan las voces de los vendedores dentro de nuestra casa aún cuan

lutik1710 [3]

Answer:

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3 years ago

The block has a weight of 75 lblb and rests on the floor for which μkμk = 0.4. The motor draws in the cable at a constant rate o

WINSTONCH [101]

The given question is incomplete. The complete question is as follows.

The block has a weight of 75 lb and rests on the floor for which $\mu k$ = 0.4. The motor draws in the cable at a constant rate of 6 ft/sft/s. Neglect the mass of the cable and pulleys.

Determine the output of the motor at the instant $\theta = 30^{o}$ .

Explanation:

We will consider that equilibrium condition in vertical direction is as follows.

$\sum F_{y} = 0$

N - W = 0

N = W

or, N = 75 lb

Again, equilibrium condition in the vertical direction is as follows.

$\sum F_{x} = 0$

$T_{2} - F_{k}$ = 0

$T_{2} = \mu_{k} N$

= $0.4 \times 75 lb$

= 30 lb

Now, the equilibrium equation in the horizontal direction is as follows.

$\sum F_{x} = 0$

$T Cos (30^{o}) + T Cos (30^{o}) = T_{2}$

$2T Cos (30^{o}) = T_{2}$

or, T = $\frac{T_{2}}{2 Cos (30^{o})}$

= $\frac{30}{2 Cos (30^{o})}$

= $\frac{30}{1.732}$

= 17.32 lb

Now, we will calculate the output power of the motor as follows.

P = Tv

= $17.32 lb \times 6$

= $103.92 \times \frac{1}{550} \times \frac{hp}{ft/s}$

= 0.189 hp

or, = 0.2 hp

Thus, we can conclude that output of the given motor is 0.2 hp.

3 0

3 years ago

Read 2 more answers

Factor each expression.<br>a. d2 + 8d + 7

Y_Kistochka [10]

Answer:

the answer is (d + 1) (d + 7)

8 0

3 years ago

A boy exerts a force of 9.0 N horizontally to push his sister on a sled. He pushes her through a distance of 15 m. How much work

MrRa [10]

Answer:

Work done by the boy is 135 J and is positive work.

Friction is the force acting that stops the sled and her sister.

Work done by friction is negative work.

Explanation:

Given:

Force acting on the sled by the boy is, $F=9.0\ N$

Displacement of the sled in the direction of force is, $S=15\ m$

We know that, positive work is said to be done by a force, if the force causes displacement in its own direction. Also, negative work is said to be done by a force, if the force causes displacement in the direction exactly opposite to the direction of the applied force.

Here, the force applied by the boy causes a displacement in the direction of the applied force. So, work is positive and is given as:

Work = Force × Displacement

$Work=F\times S\\Work=9\times 15=135\ J$

Therefore, the work done by the boy is positive and equal to 135 J.

Now, when the force of push is removed, then the body will experience only the frictional force in the opposite direction which eventually causes the sled to stop.

Here, the direction of force is backward while the displacement is in the forward direction. So, both of them are in opposite direction.

So, work done by frictional force is negative.

6 0

4 years ago