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OverLord2011 [107]
2 years ago
6

Why is the theoritical strngth of metals much higher than that observed experimentally

Chemistry
1 answer:
fiasKO [112]2 years ago
5 0

Not sure, but I would guess it's due to environmental factors, like heat, and imperfections in the metal. Just an educated guess, though.

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Its 4 dude i did this already
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A teacher uses a bow and arrow to demonstrate accuracy and precision. She shoots several arrows, aiming at the exact center of t
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3 years ago
What is the molarity of a stock solution if 60 mL were used to make 150 ml<br>of a .5M solution? ​
olga2289 [7]

The molarity of the stock solution is 1.25 M.

<u>Explanation:</u>

We have to find the molarity of the stock solution using the law of volumetric analysis as,

V1M1 = V2M2

V1 = 150 ml

M1 = 0.5 M

V2 = 60 ml

M2 = ?

The above equation can be rearranged to get M2 as,

M2 = $\frac{V1M1}{V2}

Plugin the values as,

M2 = $\frac{150 \times 0.5}{60}

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So the molarity of the stock solution is 1.25 M.

4 0
2 years ago
Which is the correct equation for the reaction of magnesium with hydrochloric acid to produce hydrogen gas and magnesium chlorid
djyliett [7]

Answer:

Mg(s) + 2 HCl(aq) --> MgCl 2(aq) + H 2(g)

8 0
2 years ago
The heat of vaporization of 1-pentanol is 55.5 kJ/mol, and its entropy of vaporization is 148 J/K.mol. What is the approximate b
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Answer:

Approximately 100 °C.

Explanation:

Hello,

In this case, since the entropy of vaporization is computed in terms of the heat of vaporization and the temperature as:

\Delta S_{vap}=\frac{\Delta H_{vap}}{T}

We can solve for the temperature as follows:

T=\frac{\Delta H_{vap}}{\Delta S_{vap}}

Thus, with the proper units, we obtain:

T=\frac{55500J/mol}{148J/(mol*K)} =375K\\\\T=102 \°C

Hence, answer is approximately 100 °C.

Best regards.

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2 years ago
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