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erma4kov [3.2K]
3 years ago
14

A 951g sample of carbon steel with a specific heat capacity of .49j is heated to 673k and quenched in oil. The steel cools to 52

3k. assuming there is no heat lost to surroundings, calculate the heat absorbed by oil.
Chemistry
2 answers:
dexar [7]3 years ago
7 0

Answer:

its 69.9

Explanation:

yw

nikdorinn [45]3 years ago
5 0

Answer: all I know it’s not -31.5 for ppl taking the k12 test

Explanation: I took the test

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Does yeast need air to release carbon dioxide
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8 0
3 years ago
I'm stuck on this assignment, +20 PTS and BRAINLIEST for step by step:
dolphi86 [110]

Answer:

2. 2.74 L

3. 488 K

4. 7.47 L

5. 38.6 L

6. 2.85 mol

7. 319 K

8. 3.43 kPa

Explanation:

Generally speaking, you want to convert units to SI units, but in this case, we are working with ratios.  This makes up for using the units that wouldn't appropriate elsewhere.

2.  Use the equation P₁V₁ = P₂V₂.  Solve for V₂.  

(3.05 L)(870 kPa) = (969 kPa)(V₂)  

V₂ = 2.74 L.  

3.  Use the equation V₁/T₁ = V₂/T₂. Solve for T₂.  

(3.32 L)/(360 K) = (4.50 L)/(T₂)  

T₂ = 488 K.

4.  Do the same as above, but for V₂.  

(5.10 L)/(-56°C) = V₂/(-82°C)  

V₂ = 7.47 L

5.  Use the equation V₁/n₁ = V₂/n₂.  Solve for V₂.  

(37.2 L)/(0.750 mol) = (V₂)/(0.778 mol)  

V₂ = 38.6 L

6.  Do the same as above, but for n₂.

(86.0 L)/(2.65 mol) = (92.5 L)(n₂)  

n₂ = 2.85 mol

7.  Use the equation P₁/T₁ = P₂/T₂.  Solve for T₂.  

(3.00 atm)/(390 K) = (2.45 atm)/(T₂)  

T₂ = 319 K

8.  Do the same as above, but for P₂.  

In this specific case, however you will need to convert units.  Since both temperatures don't have the same sign, the ratio won't come out right.  Convert to Kelvin.  Add 273.15 to the temperature in Celsius to convert to Kelvin -12.3°C = 260.85 K  25°C = 298.15 K.

(3.00 kPa)/(260.85 K) = P₂/(298.15 K)

P₂ = 3.43 kPa

There is a lot in here... If you are confused about something, let me know!

6 0
3 years ago
Hydrogen peroxide is a powerful oxidizing agent; it is used in concentrated solution in rocket fuel and in dilute solution in ha
Anestetic [448]

The molarity of the hydrogen peroxide solution from the information supplied in the question is 12.26 M.

Co = 10pd/M

Where;

Co = concentration = ?

p = percent of the hydrogen peroxide =  30%

d = Density of hydrogen peroxide =  1.39 g/ml

M = Molar mass  = 34 g/mol

Substituting values;

Co = 10 × 30 ×  1.39/34

Co = 12.26 M

The molarity of the hydrogen peroxide solution from the information supplied in the question is 12.26 M.

Learn more: brainly.com/question/6111443

4 0
2 years ago
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