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EastWind [94]
3 years ago
7

What is the mass of 22.4 L of H2O at STP?

Chemistry
1 answer:
LuckyWell [14K]3 years ago
5 0
We can find the number of moles of water at STP conditions using the ideal gas law equation
PV = nRT
Where P - standard pressure - 1 atm
V - 22.4 L
n - number of moles
R - universal gas constant - 0.0821 L.atm/mol.K
T - standard temperature- 273 K
Substituting the values in the equation
1 atm x 22.4 L = n x 0.082057 L.atm/mol.K x 273 K
n = 1.00 mol
Therefore number of water moles are 1.00 in 22.4 L
This is called the molar volume, 1 mol of any gas occupies a volume of 22.4 L at STP
Molar mass of H2O is 18.02 g/mol
Mass of water is 18.02 g/mol
Answer is A. 18.02 g/mol
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Explanation:

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Given the reactant side of the total ionic equation for the neutralization reaction of lithium hydroxide (LiOH) with hydrochlori
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<span>Answer:
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</span><span>Li⁺ (aq) + OH⁻ (aq) + H⁺ (aq) + Cl⁻(aq) → Li⁺ (aq) + Cl⁻ (aq) + H₂O(l)</span><span />

<span>Explanation:
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<span>2) Combine the anion OH⁻ with the cation H⁺ to form H₂O(l).
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<span>3) Finally, you can wirte the total ionic equation:
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Li⁺ (aq) + OH⁻ (aq) + H⁺ (aq) + Cl⁻(aq) → Li⁺ (aq) + Cl⁻ (aq) + H₂O(l)



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