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3 years ago

Give examples of partially miscible liquids.

Chemistry

2 answers:

SpyIntel [72]3 years ago

5 0

Answer:

honey and water, butanol and water, and potassium chloride and water.

Explanation:

olganol [36]3 years ago

3 0

Answer:

A pair of liquids, like 1-butanol and water, which separates into two layers, but still partially mix, is said to be partially miscible.A pair of liquids is considered partially miscible if there is a set of compositions over which the liquids will form a two-phase liquid system. ... And then at some temperature (known as the upper critical temperature), the liquids become miscible in all compositions.Some examples of miscible solutions include water and organic compounds such as alcohols, aldehydes and ketones. Immiscible solutions include water and many types of oils. A miscible solution is any solution that can be mixed together to form one liquid phase.This idea of solubility can be extended to the interactions between two liquids. If two liquids with similar polarities (and, therefore, similar intermolecular interactions) are combined, the liquids are said to be miscible with each other because the will mix to form a homogeneous solution.

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sarah measures out 151 grams of SO2. how many moles is this? Express your answer to three significant figures.

svp [43]

150 g SO₂ = 2.36 mol SO₂

M_r = 32.06 + 2×16.00 = 32.07 + 32.00 = 64.06

Moles of SO₂ = 151 g SO₂ × [1 mol SO₂/64.06 g SO₂] = 2.36 mol SO₂

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3 years ago

NaOH is an Arrhenius base because it increases the concentration of hydroxide ions when dissolved in solution.

Licemer1 [7]

The answer is true, NaOH is and Arrhenius base.

7 0

3 years ago

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Write a balanced half-cell equation for the reaction occurring at the anode. ignore phases in the reaction.

r-ruslan [8.4K]

The balanced half-cell equation for the reaction occurring at the anode is H2 ---> 2H(+) + 2e(-)

E<u>xplanation:</u>

The balanced half-cell equation taking place at the anode is explained below
The product produced in the reaction in the fuel cell is water.
H2 ---> 2H(+) + 2e(-)
In the above reaction, the oxidation state of hydrogen switches from 0 to +1.
It is becoming oxidized by delivering two electrons at the anode.
In the fuel cell, hydrogen molecules get oxidized to hydronium ions.Thus half-reaction is the oxidation reaction.

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3 years ago

Excess Ca(OH)2 is shaken with water to produce a saturated solution. The solution is filtered, and a 50.00 mL sample titrated wi

julia-pushkina [17]

<u>Answer:</u> The $K_{sp}$ for calcium hydroxide is $5.324\times 10^{-6}$

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HCl$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is $Ca(OH)_2$

We are given:

$n_1=1\\M_1=0.0983M\\V_1=11.22mL\\n_2=2\\M_2=?M\\V_2=50mL$

Putting values in above equation, we get:

$1\times 0.0983\times 11.22=2\times M_2\times 50\\\\M_2=0.011M$

The concentration of $Ca(OH)_2$ comes out to be 0.011 M.

The balanced equilibrium reaction for the ionization of calcium hydroxide follows:

$Ca(OH)_2\rightleftharpoons Ca^{2+}+2OH^-$

The expression for solubility constant for this reaction follows:

$K_{sp}=[Ca^{2+}][OH^-]^2$

Putting the values in above equation, we get:

$K_{sp}=(0.011)\times (2\times 0.11)^2$

$K_{sp}=5.324\times 10^{-6}$

Hence, the $K_{sp}$ for calcium hydroxide is $5.324\times 10^{-6}$

6 0

3 years ago

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Grignard reagents are air-and moisture-sensitive. List at least threereactants, solvents, and/or techniques that were utilized i

Evgesh-ka [11]

<h2>Diethylether (DTH) andTetrahydrofuran (THF).</h2>

Explanation:

Grignard reactions reacts with water forming alkanes.
The water present causes the reagent to decompose rapidly.

So, the solvents which are utilized in the experimental procedure to minimize exposure of the grignard reagents to air and/ormoisture are solvents such as anhydrous diethyl ether or tetrahydrofuran(THF), poly(tetramethylene ether) glycol (PTMG).

The reason for the use of these solvents is the oxygen present in these solvents stabilizes the magnesium reagent.

THF (Tetrahydrofuran) is a stable compound.

4 0

4 years ago