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neonofarm [45]
3 years ago
5

A physical (beam) is used to measure?​

Physics
2 answers:
murzikaleks [220]3 years ago
7 0

Answer:

the weight of something, that is

Explanation:

to compare weights

Kisachek [45]3 years ago
6 0

Answer:

mass of a object is the answer

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Please help don’t know how to show my work
Fudgin [204]

Answer:

64.50816

Explanation:

3 0
3 years ago
If the water in a lake is everywhere at rest, what is the pressure as a function of distance from the surface? The air above the
Rudiy27

Answer:

Answer:

101325 + 10055.25h

//

h = 10.1 m

Explanation:

the pressure at sea level =  1 atm = 101325 Pa

density of sea water = 1025 kg/ m^(3)

pressure due to fluid height = pgh

Absolute pressure = 101325 + 1025*9.81*h

                               = 101325 + 10055.25h

where h= 0 at sea level at increases downwards

//

101325 = 1025* 9.81* h

h = 10.1 m

Explanation:

7 0
3 years ago
KI + Cl2 ---&gt; KCl + I2<br> Balance the single replacement chemical reaction.
snow_lady [41]

Answer:

2KI   +  Cl₂   →   2KCl     +    I₂

Explanation:

The reaction equation is given as:

        KI   +  Cl₂   →    KCl     +    I₂

The problem at hand is to balance this chemical reaction. To solve this problem we use a mathematical approach;

        aKI   +  bCl₂   →    cKCl     +    dI₂

 Conserving K : a = c

                     I :  a  = 2d

                   Cl : 2b = c  

 Now let a = 1, c  = 1 , d  = \frac{1}{2}, b   = \frac{1}{2}, ;

   Multiply through by 2;

             a  = 2, b = 1 , c = 2, d  = 1

 

            2KI   +  Cl₂   →   2KCl     +    I₂

 

5 0
3 years ago
What is the acceleration of a 10kg rock falling at a gravitational fiend of 10N/kg​
Archy [21]

Answer:

10N/kg...................

6 0
3 years ago
The hockey player is moving at a speed of 9. 5 m/s. if it takes him 2 seconds to come to a stop under constant acceleration, how
Lunna [17]

Answer:

9.5\; {\rm m}.

Explanation:

Let u and v denote the velocity of this hockey player before and after stopping, respectively. The question states that u = 9.5\; {\rm m\cdot s^{-1}} and implies that v = 0\; {\rm m\cdot s^{-1} since the hockey player has come to a stop.

The duration of this acceleration is t = 2\; {\rm s}.  

Since the acceleration of this hockey player was constant, SUVAT equation would apply. In particular, the SUVAT equation x = (1/2)\, (v + u) \, (t) gives the displacement x of this hockey player during that 2\; {\rm s} of acceleration:

\begin{aligned} x &= \frac{1}{2}\, (9.5\; {\rm m\cdot s^{-1}} + 0\; {\rm m\cdot s^{-1}})\, (2\; {\rm s}) = 9.5\; {\rm m} \end{aligned}.

In other words, this hockey player would have travelled 9.5\; {\rm m} while stopping.

8 0
2 years ago
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