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2 years ago

What is the total potential difference provided by the four cells in the circuit each of 1.5volts?

Physics

1 answer:

aivan3 [116]2 years ago

4 0

Answer:

Answers 2.( a) . (i)Total potential difference provided by the four cell = 4x 1.5 Volts = 6.0 Volts (ii)The component of X is a variable resistor .

Explanation:

hope it helps

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Suppose you want to to double a copper wire's resistance. To what temperature, in degrees Celsius, must you raise it if it is or

sleet_krkn [62]

Answer:

T=280.41 °C

Explanation:

Given that

At T= 24°C Resistance =Ro

Lets take at temperature T resistance is 2Ro

We know that resistance R given as

R= Ro(1+αΔT)

R-Ro=Ro αΔT

For copper wire

α(coefficient of Resistance) = 3.9 x 10⁻³ /°C

Given that at temperature T

R= 2Ro

Now by putting the values

R-Ro=Ro αΔT

2Ro-Ro=Ro αΔT

1 = αΔT

1 = 3.9 x 10⁻³ x ΔT

ΔT = 256.41 °C

T- 24 = 256.41 °C

T=280.41 °C

So the final temperature is 280.41 °C.

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2 years ago

What does more damage; a slow semi truck, or a fast sports car

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The fast sports car does more damage then the slow semi truck

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2 years ago

Uma wants to recreate the discovery of superconductivity. Which describes the materials needed?

zaharov [31]

Answer:

B)a tool to drop temperatures, mercury, an electric current, and a tool to measure resistance

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2 years ago

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Write an expression for a harmonic wave with an amplitude of 0.19 m, a wavelength of 2.6 m, and a period of 1.2 s. The wave is t

zlopas [31]

Answer:

$y = 0.19 sin(5.23 t - 2.42x + \frac{\pi}{2})$

Explanation:

As we know that the wave equation is given as

$y = A sin(\omega t - k x + \phi_0)$

now we have

$A = 0.19 m$

$\lambda = 2.6 m$

so we have

$k = \frac{2\pi}{\lambda}$

$k = \frac{2\pi}{2.6}$

$k = 2.42 per m$

also we have

$T = 1.2 s$

so we have

$\omega = \frac{2\pi}{T}$

$\omega = \frac{2\pi}{1.2}$

$\omega = 5.23 rad/s$

now we know that at t = 0 and x = 0 wave is at y = 0.19 m

so we have

$\phi_0 = \frac{\pi}{2}$

so we have

$y = 0.19 sin(5.23 t - 2.42x + \frac{\pi}{2})$

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3 years ago

Refer to science 10 (mirror mirror on the wall)how do the height and width of the object compare with the height and width of th

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2 years ago