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Effectus [21]
3 years ago
15

An experiment is designed to test the relationship between the initial height of a basketball before it is dropped to the height

of its rebound bounce. The height of the rebound bounce is measured using a scale positioned behind the ball. In the above experiment, which condition would not be controlled?
A). the starting height of the ball
B). the surface the ball bounces on
C). the type of ball
D). the method to measure the rebound height of the ball

Physics
1 answer:
Virty [35]3 years ago
3 0

Answer:

A. The starting height of the ball

Explanation:

When we talk about controlled variables, we refer to the variable that should be kept the same throughout the experiment. The reason why we do this, is to limit anything else that is not being tested, that may affect the results of the experiment.

In the scenario given, the experiment is to see the relationship between the <u>initial height of a basketball</u> and the <u>height of its rebound bounce. </u>

So you the starting height of the ball should vary, meaning it is NOT controlled.

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I need help with this. I think I got it correct, but I wanna make sure.
kicyunya [14]

Answer:

A because the bigger it is the the more force needs to act apond it

Explanation:

3 0
3 years ago
Read 2 more answers
Calculate the work done by a force of 30 N in lifting a load of 2 kg to a height of 10 m (g = 10 m/s2)
Mars2501 [29]

Answer:

<u>300 J</u>

Explanation:

Given :

  1. Applied force = 30 N
  2. Mass = 2 kg
  3. Height = 10 m
  4. g = 10 m/s²

Work done by the force :

  • Work done = Force x Displacement
  • Work done = mg x h
  • Work done = 30 N x 10 m
  • Work done = <u>300 J</u>

<u></u>

<u><em>Note</em></u> :

  • What you have calculated is the work done by gravitational force on the object (that too, incorrectly)
  • But in the end, it asks for work done by the force of 30N
  • Hence, the given answer ~
3 0
2 years ago
If a 2500 kg car is traveling with an acceleration of 20.2 m/s/s, what is the force acting on it?
a_sh-v [17]

Answer:

50500

Explanation:

F = m x a

F = 2500kg x 20.2 m/s/S

F = 50500

4 0
3 years ago
A car is moving at 30.0 km/h when it accelerates at 2.0 m/s for 3.6 s. what is the car final speed?
Lana71 [14]

Answer:

wrong question

Explanation:

unit of acceleration is written in m/s which is wrong

3 0
4 years ago
In a fluorescent tube of diameter 4.8 cm , 2.7 × 1018 electrons (with a charge of −e) and 2.4 × 1018 positive ions (with a charg
Lesechka [4]

Answer: 0.817A

Explanation:

Assuming , that one coulomb per second of negative charge alone flow through a conductor and no positive charges flow. I.e Q=It

It means a current of one A flow in the opposite direction.

This is similar to one coulomb per second of positive charge flowing through and there is no negative charge,

In addition, the one coulomb per second of positive charge flows. This is flowing in the current direction of the previous one. Then, the total current is 2 A. Since 2 coulomb of positive charges flow through one due to real positive charge and another due to the negative charge flowing in opposite direction.The charges cannot cancel each other, because even before the current flow the conductor was neutral.

According to this, the current in the given problem is

[2.7 + 2.4] x 10 ^ 18 * 1.602 x 10^ [-19] C/s

= 0.817 A

7 0
4 years ago
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