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Effectus [21]
3 years ago
15

An experiment is designed to test the relationship between the initial height of a basketball before it is dropped to the height

of its rebound bounce. The height of the rebound bounce is measured using a scale positioned behind the ball. In the above experiment, which condition would not be controlled?
A). the starting height of the ball
B). the surface the ball bounces on
C). the type of ball
D). the method to measure the rebound height of the ball

Physics
1 answer:
Virty [35]3 years ago
3 0

Answer:

A. The starting height of the ball

Explanation:

When we talk about controlled variables, we refer to the variable that should be kept the same throughout the experiment. The reason why we do this, is to limit anything else that is not being tested, that may affect the results of the experiment.

In the scenario given, the experiment is to see the relationship between the <u>initial height of a basketball</u> and the <u>height of its rebound bounce. </u>

So you the starting height of the ball should vary, meaning it is NOT controlled.

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A 10-foot ladder is leaning straight up against a wall when a person begins pulling the base of the ladder away from the wall at
docker41 [41]

Answer:

y = 4.36

Explanation:

Let the height of the ladder be L

L = 10

Also:

  • Let x = distance\ from\ the\ base\ of\ the\ ladder
  • Let y = height\ of\ the\ base\ of\ the\ ladder

When the ladder leans against the wall, it forms a triangle and the length of the ladder forms the hypotenuse.

So, we have:

L^2 = x^2 + y^2 --- Pythagoras Theorem

When the base is 9ft from the wall, this means that:

x = 9

Substitute 9 for x and 10 for L in L^2 = x^2 + y^2

10^2 = 9^2 + y^2

100 = 81 + y^2

Make y^2 the subject

y^2 = 100 - 81

y^2 = 19

Make y the subject

y = \sqrt{19

y = 4.36

<em>Hence, the true distance at that point is approximately 4.36ft</em>

8 0
3 years ago
Two point charges exert a 5.00 N force on each other. What will the force become if the distance between them is increased by a
weeeeeb [17]

Answer:

force becomes one - ninth

Explanation:

According to Coulomb's law in electrostatics, two charges can exert a force of attraction or repulsion on each other which is directly proportional to the product of two charges and inversely proportional to the square of distance between them.

Here both the charges remains same but the distance is variable.

So, we can say that

F \alpha \frac{1}{d^{2}}    .... (1)

Where d be the distance between the tow charges

As the distance between two charges increases by factor of three, let the new force be F'.

F' \alpha \frac{1}{9d^{2}}   .... (2)

Divide equation (2) by equation (1), we get

\frac{F'}{F}=\frac{d^{2}}{9d^{2}}

F'=\frac{F}{9}

Thus, the force becomes one - ninth times the initial force.

6 0
3 years ago
Two men are standing on a frictionless ice surface holding opposite ends of a rope. One man (mass = 80 kg) pulls on the rope wit
ankoles [38]

Answer:

The acceleration of man 1 and 2 is 3.125\ m/s^2 and 4.167\ m/s^2.

Explanation:

Mass of man 1, m₁ = 80 kg

Mass of man 2, m₂ = 60 kg

One man pulls on the rope with a force of 250 N.

Let a₁ is acceleration of man 1,

F = m₁a₁

a_1=\dfrac{F}{m_1}\\\\a_1=\dfrac{250}{80}\\\\a_1=3.125\ m/s^2

Let a₂ is acceleration of man 1,

F = m₂a₂

a_2=\dfrac{F}{m_2}\\\\a_2=\dfrac{250}{60}\\\\a_2=4.167\ m/s^2

So, the acceleration of man 1 and 2 is 3.125\ m/s^2 and 4.167\ m/s^2.

7 0
3 years ago
A large sheet of charge has a uniform charge density of 9  μCm2. What is the electric field due to this charge at a point just
Alex73 [517]

Answer:

Explanation:

Surface charge density, σ = 9 μC/m² = 9 x 10^-6 C/m²

According to the Gauss theorem,

Electric field due to the sheet is given by

E = \frac {\sigma }{2\epsilon _{0}}

E = \frac{9\times 10^{-6}}{2\times 8.854\times 10^{-12}}

E = 5.08 x 10^5 N/C

7 0
3 years ago
In a compoumd are atoms physically or chemically combined
Andrei [34K]

Answer:

They are...if I'm correct Chemically combined, sorry if I'm wrong.

3 0
2 years ago
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