When an electron is added to a neutral atom of an element to form a negative ion, the resulting change in energy is referred to
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Complete question:
Two 10-cm-diameter charged rings face each other, 21.0 cm apart. Both rings are charged to +40.0 nC. What is the electric field strength at the midpoint between the two rings ?
Answer:
The electric field strength at the mid-point between the two rings is zero.
Explanation:
Given;
diameter of each ring, d = 10 cm = 0.1 m
distance between the rings, r = 21.0 cm = 0.21 m
charge of each ring, q = 40 nC = 40 x 10⁻⁹ C
let the midpoint between the two rings = x
The electric field strength at the midpoint between the two rings is given as;
Therefore, the electric field strength at the mid-point between the two rings is zero.
Here it is given that speed of migrating Robin is 12 m/s relative to air
so we can say that
North
so it will be
Let North direction is along Y axis and East direction is along X axis
also it is given that speed of air is 6.7 m/s relative to ground
now as we know by the concept of relative motion
now by rearranging the terms
now we need to find the speed of Robin which means we need to find the magnitude of its velocity which we found above
So here we will say
so the net speed of Robin with respect to ground will be 13.7 m/s