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maria [59]
3 years ago
12

Charles Lindbergh, for his attempt at a solo transatlantic flight, was very reluctant to have any extra weight on his plane, he

therefore refused to carry even a pound of mail, despite being offered $1,000 to do so.
(A) Charles Lindbergh, for his attempt at a solo transatlantic flight, was very reluctant to have any extra weight on his plane, he therefore
(B) When Charles Lindbergh was attempting his solo transatlantic flight, being very reluctant to have any extra weight on his plane, he
(C) Since he was very reluctant to carry any extra weight on his plane when he was attempting his solo transatlantic flight, so Charles Lindbergh
(D) Being very reluctant to carry any extra weight on his plane when he attempted his solo transatlantic flight was the reason that Charles Lindbergh
(E) Very reluctant to have any extra weight on his plane when he attempted his solo transatlantic flight, Charles Lindbergh
Physics
1 answer:
CaHeK987 [17]3 years ago
3 0

Very reluctant to have any extra weight on his plane when he attempted his solo transatlantic flight, Charles Lindbergh

Explanation:

““Very reluctant” appropriately modifies the subject of the Equal clause Charles Lindbergh.  

Nevertheless, Charles Lindberg addresses the sentence in the question. And claim that, "It was... the justification and be reluctant" renders Lindberg's hesitation rather than Lindberg himself immune to the judgment.

In comparison to sounding wordy, this structure deliberately undermines the essence of the expression by moving the emphasis to a tangential topic.

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Which of the following is NOT a valid reason that less energy is transferred at each level of the food chain?
stealth61 [152]

Answer:

B.

Explanation:

I'm pretty sure the answer is B because animals at the top need a lot of energy, so to make up for loss of energy at the higher levels, those organisms at the top have to consume a lot more.

5 0
3 years ago
Pls answer these ASAP....THANK YOU...
natali 33 [55]

Density = (mass) / (volume) <== MEMORIZE THIS !

1).  Mass = 50 g.  Volume = 100 cm³.  Density = (mass) / (volume)

===================================

2).  Volume = (length) ·(width) ·(height) = (4cm) ·(4cm) ·(4cm) = 64 cm³

Mass = 672 g.  Density = (mass) / (volume)

===================================

3).  Volume = (length) ·(width) ·(height)

Length = 1 meter = 100 cm

Width = 10 cm = 10 cm

Height = 22 mm = 2.2 cm

Volume = (100 cm) (10 cm) (2.2 cm) = 2,200 cm³

Mass = 42,460 g

Density = (mass) / (volume)

3 0
3 years ago
A piece of taffy slams into and sticks to an identical piece of taffy at rest. The momentum of the combined pieces after the col
Marina CMI [18]

Answer:

D) 50%

Explanation:

According to conservation of momentum:

m_{1} v_{1i} + m_{2} v_{2i} = m_{1} v_{1f} + m_{2} v_{2f}

Assuming that the second taffy started at rest, both pieces have the same mass and that they combined after the collision, their final velocity is:

m v_{1i} = (m+m) v_{f}\\v_{f} = 0.5 v_{1i}

The initial kinetic energy of the system is:

E_{ki} = \frac{m*v_{1i}^2}{2}

Since the second taffy was not moving, it had no kinetic energy at first.

The initial kinetic energy of the system is:

E_{kf} = \frac{2m*v_{f}^2}{2}\\E_{kf} = \frac{2m*(0.5v_{1i})^2}{2}\\E_{kf} = \frac{0.5m*v_{1i}^2}{2}

The percentage of kinetic energy that becomes heat is given by:

H=1 - \frac{E_{kf}}{E_{ki}}\\H=1 - \frac{\frac{0.5m*v_{1i}^2}{2}}{\frac{m*v_{1i}^2}{2}}\\\\H=1- 0.5 = 0.5

THerefore, 50% of the kinetic energy becomes heat

8 0
3 years ago
Which process changes light energy to heat? Question 6 options: refraction absorption reflection none of the above
sergey [27]
None of the above!!!!!!!!!??????????$
3 0
3 years ago
A diatomic molecule is rotating about its center of mass with an angular speed of 3.90 ✕ 10^12 rad/s. Determine the rotational k
Novosadov [1.4K]

Answer:

E_s = 7.35\times 10^{-22}\ J

Explanation:

given,

angular speed, ω = 3.90 x 10¹² rad/s

bond length, L = 1.10 Å

molar mass = 28.0 g/mole

Rotational Kinetic energy

E_s = \dfrac{1}{2} I \omega^2

now,

moment of inertia ,I = \dfrac{1}{2}MR^2......(1)

mass of O₂ = m

mass of O = M = m/2

now, mass

M = \dfrac{28\times 1.67\times 10^{-27}}{2}

form equation(1)

I = \dfrac{1}{2}\times \dfrac{28\times 1.67\times 10^{-27}}{2}\ R^2

I = \dfrac{1}{2}\times \dfrac{28\times 1.67\times 10^{-27}}{2}\ (1.10\times 10^{-10})^2

 I = 9.66 x 10⁻⁴⁷ kg.m²

putting value in Rotational kinetic energy equation

E_s = \dfrac{1}{2}\times 9.66\times 10^{-47}(3.9\times 10^{12})^2

E_s = 7.35\times 10^{-22}\ J

Hence, rotational kinetic energy of the molecule is equal to E_s = 7.35\times 10^{-22}\ J

6 0
3 years ago
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