How long would a circuit be connected to produce a current of 0.65 A with a charge of 380 C?

If the block is subjected to the force of F = 500 N, determine its velocity at s = 0.5 m. When s = 0, the block is at rest and t

STatiana [176]

Answer:

The velocity is $4.6 m/s^2$

Explanation:

Given:

Force = 500N

Distance s= 0

To find :

Its velocity at s = 0.5 m

Solution:

$\sum F_{x}=m a$

$F\left(\frac{4}{5}\right)-F_{S}=13 a$

$500\left(\frac{4}{5}\right)-\left(k_{s}\right)=13 a$

$400-(500 s)=13 a$

$a = \frac{400 -(500s)}{13}$

$a = (30.77 -38.46s) m/s^2$

Using the relation,

$a=\frac{d v}{d t}=\frac{d v}{d s} \times \frac{d s}{d t}$

$a=v \frac{d v}{d s}$

$v d v=a d s$

Now integrating on both sides

$\int_{0}^{v} v d v=\int_{0}^{0.5} a d s$

$\int_{0}^{v} v d v=\int_{0}^{0.5}(30.77-38.46 s) d s$

$\left[\frac{v^{2}}{2}\right]_{0}^{2}=\left[\left(30.77 s-19.23 s^{2}\right)\right]_{0}^{0.5}$

$\left[\frac{v^{2}}{2}\right]=\left[\left(30.77(0.5)-19.23(0.5)^{2}\right)\right]$

$\left[\frac{v^{2}}{2}\right]=[15.385-4.807]$

$\left[\frac{v^{2}}{2}\right]=10.578$

$v^{2}=10.578 \times 2$

$v^{2}=21.15$

$v = \sqrt{21.15}$

$v = 4.6 m/s^2$

8 0

3 years ago

If we increase the driving frequency in a circuit with purely resistive load, how do the amplitudes VR and IR change?

Lady_Fox [76]

Answer:

V = I R

expression does not depend on the frequency, so when changing this quantity does not change the voltage or the current in the circuit.

Explanation:

In a purely resistive circuit, the Ohm relation, m for which

V = I R

We see that the previous expression does not depend on the frequency, so when changing this quantity does not change the voltage or the current in the circuit.

This does not happen in circuits with capacitors or inductors where there is an explicit dependence on frequency.

3 0

3 years ago

All atoms contain negatively charged ____________ that orbit around a positively charged nucleus.

S_A_V [24]

Answer: Electron

In atom, there are proton and neutron inside the nucleus and electron which was moving in orbit outside of the nucleus. The electron is a negatively charged, a proton is positively charged and neutron is neutral. Since there are only proton and neutron in the nucleus it's become positively charged.

7 0

3 years ago

In a Young's double-slit experiment, a set of parallel slits with a separation of 0.114 mm is illuminated by light having a wave

elena-14-01-66 [18.8K]

Answer:

a) 2232nm

b) 2511nm

Explanation:

a) To find the path difference Δl you use the following formula:

$\Delta l=m\lambda$