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kiruha [24]
3 years ago
8

How long would a circuit be connected to produce a current of 0.65 A with a charge of 380 C?

Physics
1 answer:
drek231 [11]3 years ago
3 0

Answer:

what grade are you dude

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edward travels 150 kilometers due west and then 200 kilometers in a direction 60 degrees north of west.what is his displacement
laila [671]

The displacement of Edward in the westerly direction is determined as 180.27 km.

<h3>Displacement of Edward</h3>

The displacement of Edward is calculated as follows;

R² = a² + b² - 2abcosθ

R² = 150² + 200² - 2(150 x 200) x cos60

R² = 32500

R = 180.27 km

Thus, the displacement of Edward in the westerly direction is determined as 180.27 km.

Learn more about displacement here: brainly.com/question/321442

#SPJ1

3 0
2 years ago
A ball rolls to the right across a grassy field slowing down as it does so. Which of the following must be true?
In-s [12.5K]

Answer: i could prolly answer if it made more sense. which of the following where?

5 0
3 years ago
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I want ti know how to study​
arlik [135]

Answer:

Make sure everything is organized have a planner it can help

Get rid of all distractions

Listen to music if it helps you concentrate

Have your notes

Being willing to stay focus on what you are doing

Understand what you are doing

And most off all Be Happy and Remain Calm : )

3 0
4 years ago
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Can someone help me with this? (The answer marked in red text is a incorrect answer)
KIM [24]

I think the answer is A

Explanation:

the bus has more kg than the car so. the bus need to stop first

6 0
2 years ago
It has been suggested that rotating cylinders about 17.0 mi long and 4.99 mi in diameter be placed in space and used as colonies
Sladkaya [172]

Answer:

\omega = 49.86*10^{-3}rad/s

Explanation:

We start converting to SI units,

A mile = 1609m

L=17mi=27000m

D=4.99mi=7884m

We know that the expression, which can relate linear acceleration and angular velocity is given by,

a_c = r\omega^2

Where \omega is the angular velocity

r=radius

a_c = linear acceleration,

Re-arrange for \omega,

\omega = \sqrt{\frac{a_c}{r}}

Our acceleration is equal to the gravity force, so replacing,

\omega = \sqrt{\frac{9.8}{(7884/2)}}

\omega = 49.86*10^{-3}rad/s

8 0
4 years ago
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