How long would a circuit be connected to produce a current of 0.65 A with a charge of 380 C?

Uma wants to recreate the discovery of superconductivity. Which describes the materials needed?

zaharov [31]

Answer:

B)a tool to drop temperatures, mercury, an electric current, and a tool to measure resistance

7 0

2 years ago

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On your first trip to Planet X you happen to take along a 280 g mass, a 40-cm-long spring, a meter stick, and a stopwatch. You'r

arsen [322]

Answer:

5.31143691523 m/s²

Explanation:

m = Mass = 280 g

x = Displacement of spring = 21.7 cm

Time period

$T=\dfrac{14}{11}\\\Rightarrow T=1.27\ s$

Angular velocity is given by

$\omega=\dfrac{2\pi}{T}\\\Rightarrow \omega=\dfrac{2\pi}{1.27}\\\Rightarrow \omega=4.94739\ rad/s$

$\omega=\sqrt{\dfrac{k}{m}}\\\Rightarrow k=\omega^2m\\\Rightarrow k=4.94739^2\times 0.28\\\Rightarrow k=6.85346698739\ N/m$

From Hooke's law

$mg=kx\\\Rightarrow g=\dfrac{kx}{m}\\\Rightarrow g=\dfrac{6.85346698739\times 0.217}{0.28}\\\Rightarrow g=5.31143691523\ m/s^2$

The acceleration due to gravity on the planet is 5.31143691523 m/s²

Yes, I have been able to satisfy my curiosity.

7 0

2 years ago

Would a measured force of (46.5 0.8 N  ) be in agreement with a theoretically calculated force of (48.4 0.6 N  ) ? Show your w

OverLord2011 [107]

Answer:

A measured force of (46.5 0.8 N  ) would not be in agreement with a theoretically calculated force of (48.4 0.6 N  )

Explanation:

From the question we are told that

Measured force is $F_M = [46.5 \pm 0.8 \ N ]$

Calculated force is $F_c = [48.4 \pm 0.6 \ N ]$

Generally the measured force in interval form is

$46.5 - 0.8 < F_M < 46.5 + 0.8$

=> $45.7 < F_M < 47.3$

Generally the calculated force in interval form is

$48.4 - 0.6 < F_c < 48.4 + 0.6$

=> $47.8 < F_M$

Generally looking both interval we see that they do not intersect at any point Hence

A measured force of (46.5 0.8 N  ) would not be in agreement with a theoretically calculated force of (48.4 0.6 N  )

8 0

1 year ago

If a pendulum has a period of 4 seconds at the north pole with gravity force 9.83 ms^-2 and a 3.97m pendulum length, how could t

sladkih [1.3K]

Answer:

The same pendulum could be adjusted to have the same period, in the equator must have a length of 3.949m.

Explanation:

Tnp= 4 sec

gnp= 9.83 m/sec²

Lnp= 3.97m

Tequ= 4 sec

gequ= 9.78 m/sec²

Lequ=?

Lequ= (Lnp* gequ) / gnp

Lequ= 3.949 m

5 0

2 years ago

Scientists use sonar machines in order to map the contour of the ocean floor. The data from the sonar machines make a model of t

Leviafan [203]

It would be B. since the scanning shows what the terrain is down there

(I listened)

8 0

3 years ago

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