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olga55 [171]
3 years ago
6

Technician A says damage can occur to solid-state circuitry if the charging voltage is allowed to get too high. Technician B say

s damage can occur if the vehicle is allowed to run with the battery disconnected. Who is correct?
Engineering
1 answer:
tresset_1 [31]3 years ago
7 0

Answer:

Both Technicians A and B are correct

Explanation:

A solid-state circuitry is usually composed of semi-conductor materials. When a higher voltage than usual is introduced to the circuitry it can cause overheating and damage the various semi-conductor materials that compose the solid-state circuitry. So the technician A is correct.

Disconnecting a car batter while the vehicle is allowed to run can damage the electronic components in the car. Asides providing electricity to the car, the battery also shorts AC, spikes and transients to ground. If you remove the battery while the vehicle is running, the spikes and transients will simply be transferred to your vehicle's electronics and damage them. So the technician B is also correct.

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Using the tables for water determine the specified property data at the indicated state. For H2O at T = 140 °C and v = 0.2 m3/kg
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Answer:

h = 1429.74\,\frac{kJ}{kg}

Explanation:

The determination of any further properties requires the knowledge of two independent properties. (Temperature and specific volume in this case). The specific volumes for saturated liquid and vapor at 140 °C are, respectively:

\nu_{f} = 0.001080\,\frac{m^{3}}{kg}

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Since \nu_{f} < \nu < \nu_{g}, it is a liquid-vapor mixture. The quality of the mixture is:

x = \frac{\nu-\nu_{f}}{\nu_{g}-\nu_{f}}

x = \frac{0.2\,\frac{m^{3}}{kg} - 0.001080\,\frac{m^{3}}{kg} }{0.50850\,\frac{m^{3}}{kg} - 0.001080\,\frac{m^{3}}{kg} }

x = 0.392

The specific enthalpies for saturated liquid and vapor at 140 °C are, respectively:

h_{f} = 589.16\,\frac{kJ}{kg}

h_{g} = 2733.5\,\frac{kJ}{kg}

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h = 589.16\,\frac{kJ}{kg}+0.392\cdot \left( 2733.5\,\frac{kJ}{kg} - 589.16\,\frac{kJ}{kg} \right)

h = 1429.74\,\frac{kJ}{kg}

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