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lilavasa [31]
3 years ago
12

Are Zombies Living or Non-living Reasoning and Evidence?

Chemistry
1 answer:
Thepotemich [5.8K]3 years ago
7 0

Answer:

I believe that zombies are not living

Explanation:

because zombies don't grow and develop because they are practically mindless. Also, zombies definitely respond to the environment (like when they see a human) but they don't adapt to it

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Which of these is an example of a chemical reaction that occurs at a very fast rate?
Aloiza [94]
I believe the answer is an explosion
7 0
3 years ago
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A welding torch produces a flame by burning acetylene fuel in the presence of oxygen the energy released from the acetylene fuel
Volgvan
Answer : Chemical energy to thermal energy

Explanation : When the welding torch uses the acetylene fuel for producing flame it is using the chemical acetylene to generate energy in form of light, after the flame is produced the fuel is used for melting a metal which is utilizing the thermal energy. So the ultimate final product is generated from chemical to thermal and so the energy transformation is from chemical energy to thermal energy.
8 0
3 years ago
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Use the periodic table to determine the electron configuration for Ca and Pm in noble-gas notation Ca: [Ar]4s2 [Ar]4s1 [Ar]3s2 [
sveta [45]
Answer:

1) Ca: [Ar]4s²
2) Pm: [Xe]6s²4f⁵

Explanation:

1) Ca:

Its atomic number is 20. So it has 20 protons and 20 electrons.

Since it is in the row (period) 4 the noble gas before it is Ar, and the electron configuration is that of Argon whose atomic number is 18.

So, you have two more electrons (20 - 18 = 2) to distribute.

Those two electrons go the the orbital 4s.

Finally, the electron configuration is [Ar] 4s².

2) Pm

The atomic number of Pm is 61, so it has 61 protons and 61 electrons.

Pm is in the row (period) 6. So, the noble gas before Pm is Xe.

The atomic number of Xe is 54.

Therefore, you have to distribute 61 - 54 = 7 electrons on the orbitals 6s and 4f.

The resultant distribution for Pm is: [Xe]6s² 4f⁵.
5 0
3 years ago
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A balloon filled with 1.22 L of gas at 286 K is heated until the
TiliK225 [7]

Answer: 670K

Explanation:

Given that,

Original volume of gas V1 = 1.22 L

Original temperature T1 = 286 K

New volume V2 = 2.86 L

New temperature T2 = ?

Since volume and temperature are involved while pressure is constant, apply the formula for Charles law

V1/T1 = V2/T2

1.22 L/286 K = 2.86 L/ T2

Cross multiply

1.22 L x T2 = 286 K x 2.86 L

1.22T2 = 817.96

Divide both sides by 1.22

1.22T2/1.22 = 817.96/1.22

T2 = 670.459 K (Round to the nearest whole number as 670 K)

Thus, the temperature of the gas is 670 Kelvin

4 0
3 years ago
A synthesis reaction takes place when carbon monoxide (CO) and hydrogen gas (H2) react to form methanol (CH3OH). How many grams
jek_recluse [69]

The mass of methanol produced is 8.0 g.

We have the masses of two reactants, so this is a <em>limiting reactant</em> problem.

We know that we will need a <em>balanced equation</em> with masses, moles, and molar masses of the compounds involved.

<em>Step 1</em>. <em>Gather all the informatio</em>n in one place with molar masses above the formulas and everything else below them.

MM: ___28.01  2.016 ___32.04

_______CO + 2H_2 → CH_3OH

Mass/g: 7.0 __2.5

<em>Step 2</em>. Calculate the <em>moles of each reactant</em>

Moles of CO = 7.0 g CO × (1 mol CO/28.01g CO) = 0.250 mol CO

Moles of H_2 =2.5 g H_2 × (1 mol H_2/2.016 g H_2) = 1.24 mol H_2

<em>Step 3. </em>Identify the<em> limiting reactan</em>t

Calculate the <em>moles of CH_3OH</em> we can obtain from each reactant.

<em>From CO</em>: Moles of CH_3OH = 0.250 mol CO  × (1 mol CH_3OH /1 mol CO)

= 0.250 mol CH_3OH

<em>From H_2</em>: Moles of CH_3OH = 1.24 mol H_2 × (1 mol CH_3OH /2 mol H_2)

= 0.620 mol CH_3OH

<em>CO is the limiting reactant</em> because it gives the smaller amount of CH_3OH.

<em>Step 4</em>. Calculate the <em>mass of CH_3OH</em>

Mass of CH_3OH = 0.250 mol CH_3OH × (32.04 g CH_3OH /1 mol CH_3OH) = 8.0 g CH_3OH

3 0
3 years ago
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