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ioda
3 years ago
7

How many kilowatt-hours of electricity are used to produce 4.50 kg of magnesium in the electrolysis of molten mgcl2 with an appl

ied emf of 5.00 v?
Chemistry
1 answer:
ratelena [41]3 years ago
3 0
First, we need to determine the half reaction of magnesium. It would be expressed as:

Mg2+ + 2e- = Mg

Given the mass of magnesium metal that is produced, we calculate the total charge of the electrolysis by the relations we can get from the half reaction. We do as follows:

4.50 kg Mg ( 1000 g / 1 kg ) ( 1 mol / 24.305 g ) ( 2 mol e- / 1 mol Mg ) ( 96500 C / 1 mol e- ) = 35733388.2 C

We are given the applied EMF in units of V. This value is equal to J/C. So, 5 V is equal to 5 J/C.

35733388.2 C (5 J/C) = 178666941 J
178666941 J ( 1 kW-h / 3.6x10^6 J ) = 49.63 kW-h
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The recommended dietary allowance for calcium for teenage children is 1,300 mg per day.
PtichkaEL [24]

Answer:

c) 35 fl oz

Explanation:

Hello,

In this case, to compute the recommended amount of calcium that the teenager must drink, one performs the following relationship:

8.0-fl \ oz -->298mg\\x-->1,300mg

Solving for x, one gets:

x=\frac{8.0-fl \ oz *1,300mg}{298mg} \\x=35-fl \ oz

Best regards.

5 0
3 years ago
A gas occupies a volume of 50 mL and 630 mmHg. At what temperature in Celsius, would the pressure be 101.3 kPa if the volume rem
KATRIN_1 [288]

Answer:

then it would still be 101.3

Explanation: because if it's constant that means it remained still

4 0
2 years ago
When loading your sample onto the column, the solvent head should be about 0.5 cm below the top of the gel. A. True B. False
AysviL [449]
B false because it says 0.5cm on top of gel
8 0
3 years ago
Potassium hydroxide molar mass
Mnenie [13.5K]

The answer I will give is an approximate number, but it will be close. The problem is that every periodic table is slightly different. Some round as I will, and some carry the mass of the elements out to 3 decimal places. You should go back and put the correct numbers in to the mass that I use.

Formula

KOH

Givens

  • K = 39
  • O = 16
  • H = 1

Solution

Molar Mass = 39 + 16 + 1

Molar Mass = 56 grams / mole

6 0
3 years ago
Calculate each of the following:<br> (b) Mass % of Mn in potassium permanganate
Brilliant_brown [7]

Mass percent is the estimation of the mass of the element in a compound in percentage form. The mass % of manganese (Mn) in potassium permanganate is 34.76 %.

<h3>What is the mass percentage?</h3>

The mass percentage is defined by dividing the mass of the element by the molecular mass of the compound followed by multiplying it by 100%. It is given as,

Mass % =  (Atomic Mass of element ÷ Molecular Mass) × 100

As it is known that,

Atomic Mass of manganese =  54.94 g/mol

Molecular Mass of potassium permanganate =  158.034 g/mol

Substituting values to calculate mass % as:

% Mn  =  (Atomic Mass of Mn ÷ Molecular Mass of KMnO₄) × 100

= (54.94 g/mol ÷ 158.034 g/mol) × 100

= 34.76 %

Therefore, 34.76% Mn is present in KMnO₄.

Learn more about mass percentage, here:

brainly.com/question/27429978

#SPJ4

3 0
2 years ago
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