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Ahat [919]
3 years ago
9

Plsss help me :(((

Chemistry
1 answer:
dimulka [17.4K]3 years ago
5 0

Answer:

a) 3ml

b)292.5ml

c)89ml

d)49ml

e)5.8ml

f)33ml

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Can you please help with question 1 and 4​
larisa86 [58]

Answer:

i) 24.305 u

iv) The number of protons determines an element's atomic number and is used to distinguish one element from another.

5 0
3 years ago
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Do ice and snow have the same chemical bonds ​
Roman55 [17]

Yes. The only difference is snow has a weaker bond and is in regular shape particles and ice forms into sheets and such.

4 0
4 years ago
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What is the molecular formula for Tricarbon nonachloride?
vampirchik [111]

Answer:

C_{3}Cl_{9}

Explanation:

Molecular Formula is representation of the chemical compound in terms of the symbols of all the elements that are present in the compound followed by subscripts, which give the count of each element in that compound.

We need to write the molecular formula of Tricarbon nonachloride. Tri means three, so Tricarbon means there are 3 atoms of Carbon. Likewise, nona stands for 9, so nonachloride means there are 9 atoms of chlorine. Therefore, we can represent nonachloride as:

Carbon (3 atoms) Chlorine (9 atoms) = C_{3}Cl_{9}

Thus, molecular formula of Tricarbon nonachloride is C_{3}Cl_{9}

8 0
4 years ago
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You wish to prepare a buffer consisting of acetic acid and sodium acetate with a total acetic acetate plus acetate concentration
vovangra [49]

<u>Ans: Acetic acid = 90.3 mM and Sodium acetate = 160 mM</u>

Given:

Acetic Acid/Sodium Acetate buffer of pH = 5.0

Let HA = acetic acid

A- = sodium acetate

Total concentration [HA] + [A-] = 250 mM ------(1)

pKa(acetic acid) = 4.75

Based on Henderson-Hasselbalch equation

pH = pKa + log[A-]/[HA]

[A-]/[HA] = 10^(pH-pKa) = 10^(5-4.75) = 10^0.25 = 1.77

[A-] = 1.77[HA] -----(2)

From (1) and (2)

[HA] + 1.77[HA] = 250 mM

[HA] = 250/2.77 = 90.25 mM

[A-] = 1.77(90.25) = 159.74 mM



7 0
4 years ago
Consider the balanced chemical reaction when phosphorus and iodine react to produce phosphorus triodide: 2 P(s) + 3 I2(g) → 2 PI
melamori03 [73]

Answer:

Percent yield of PI3 = 95.4%

Explanation:

This is the reaction:

2P (s) + 3I2 (g) > 2PI3 (g)

Let's determine the moles of iodine that has reacted.

58.6 g / 253.8 g/mol = 0.231 mol

Ratio is 3:2. Let's make a rule of three to state the moles produced at 100 % yield reaction.

3 moles of I2 react to make 2 moles of PI3

0.231 moles of I2 would make (0.231 .2) / 3 = 0.154 moles of PI3

As we have produced 0.147 moles let's determine the percent yield.

(Yield produced / Theoretical yield) . 100 > (0.147 / 0.154) . 100 = 95.4%

5 0
3 years ago
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