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svetlana [45]
3 years ago
8

Look at the distance-time graph below. It shows Angela's journey as she walks to the end of the road and back. The gradient repr

esents Angela's __________. What one word completes the sentence?
Physics
1 answer:
sineoko [7]3 years ago
4 0

Answer:

The gradient here represents Angela's Velocity.

Explanation:

A distance-time graph has distance on its y-axis and time on its x-axis. Therefore, the gradient of the distance-time graph is given by the following formula:

Gradient = \frac{Change\ on\ y-axis}{Change\ on\ x-axis} \\\\Gradient = \frac{Distance\ Covered\ by\ Angela}{Time\ taken\ to\ cover\ the\  distance}\\\\Gradient = Angela's\ Velocity

Since the rate of change of distance is called the velocity.

<u>Therefore, the gradient here represents Angela's Velocity.</u>

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g How many diffraction maxima are contained in a region of the Fraunhofer single-slit pattern, subtending an angle of 2.12°, for
lbvjy [14]

Answer:

2

Explanation:

We know that in the Fraunhofer single-slit pattern,

maxima is given by

a\text{sin}\theta=\frac{2N+1}{2}\lambda

Given values

θ=2.12°

slit width a= 0.110 mm.

wavelength λ= 582 nm

Now plugging values to calculate N we get

0.110\times10^{-3}\text{sin}2.12=(\frac{2N+1}{2})582\times10^{-9}

Solving the above equation we get

we N= 2.313≅ 2

4 0
3 years ago
A piano string having a mass per unit length of 5.00 g/m is under a tension of 1350 N. Determine the speed of transverse waves i
padilas [110]

Answer:

The speed of transverse waves in this string is 519.61 m/s.

Explanation:

Given that,

Mass per unit length = 5.00 g/m

Tension = 1350 N

We need to calculate the speed of transverse waves in this string

Using formula of speed of the transverse waves

v=\sqrt{\dfrac{T}{\mu}}

Where, \mu = mass per unit length

T = tension

Put the value into the formula

v = \sqrt{\dfrac{1350}{5.00\times10^{-3}}}

v =519.61\ m/s

Hence, The speed of transverse waves in this string is 519.61 m/s.

6 0
3 years ago
In a mixture of the gases oxygen and helium, which statement is valid: (a) the helium molecules will be moving faster than the o
mixer [17]

Answer:

a

Explanation:

Given:

In a mixture of the gases oxygen and helium, which statement is valid:

(a) the helium molecules will be moving faster than the oxygen molecules, on average

(b) both kinds of molecules will be moving at the same speed

(c) the oxygen molecules will, on average, be moving more rapidly than the helium molecules

(d) the kinetic energy of the helium will exceed that of the oxygen

(e) none of the above

Solution:

- We will use Boltzmann distribution to answer this question. The root mean square speed of molecules of a gas gives the average speed as follows:

                                        V_rms = sqrt ( 3 k T / m )

- Where, k is the Boltzmann constant, T is the temperature and m is the mass of a single molecule of a gas.

- In general, a mixture has a constant equilibrium temperature T_eq.

- So the v_rms is governed by the mass of a single molecule.

- We know that mass of single molecule of Oxygen is higher than that of Helium molecule. Hence, the relation of mass is inversely proportional to square of root mean speed. So the helium molecules will be moving faster than the oxygen molecules.

- Note: The kinetic energy of the mixture remains constant because it is due to the interaction of the molecules within i.e oxygen and helium. Which makes the kinetic energy independent of mass.

                                     E_k = 0.5*m*v_rms^2

                                     E_k = 0.5*m*(3*k*T/ m )

                                    E_k = 0.5*3*k*T

Hence, E_k is only the function of Temperature which we already established to remain constant at equilibrium.

                                   

8 0
3 years ago
If an object 18 millimeters high is placed 12 millimeters from a diverging lens and the image is formed 4 millimeters in front o
Svetach [21]
C.
18 / x = 12 / 4
12x = 72
x = 6mm
6 0
3 years ago
Define the physics quantity of work
umka2103 [35]

Explanation:

Work done is the force applied to move a body through a specific or particular direction.

It is also the difference in the amount of energy expended in using an effort.

 Work done is given as;

 Work done  = F x d CosФ

F is the force applied

d is the displacement

Ф is the angle

 The unit of work done is in Joules.

5 0
3 years ago
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