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Ratling [72]
3 years ago
10

15. A politician campaigning for election guaran tees that "every household will have 100\% pure water from every tap." Evaluate

this prom ise and predict the likelihood of its success .
Chemistry
1 answer:
SIZIF [17.4K]3 years ago
6 0

Answer:

It is not possible to have 100 percent pure water. Therefore the success rate is not certain

Explanation:

Naturally, pure water does not exist. Water is a universal solvent. As water falls in to the earth as rain, from the atmosphere water picks up particles and minerals. Immediately water hits the ground it reacts with minerals from soil upon which it lands and then it enters into streams and rivers.

Hundred percent pure water is dangerous to life, because it has no minerals which makes it corrosive, if a hundred percent pure water enters the body it will suck off the minerals in the body.

The politician should make a promise of hundred percent pure water to the people in the industrial sector and laboratories because that is where it is useful.

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Simora [160]

Answer:

3H₂SO₄ + 2Al₂(SO₄)₃  → Al₂(SO₄)₃ + 3H₂

Explanation:

                           3H₂SO₄ + 2Al₂(SO₄)₃  → Al₂(SO₄)₃ + 3H₂

In this type of reaction, one substance is replacing another:

                      A + BC  →  AC + B

In a single displacement reaction, atoms replace one another based on the activity series. Elements that are higher in the activity series. Also, if the element that is to replace the other in a compound is more reactive the reaction will occur. If it is less reactive, there will be no reation.

In the first equation, fluorine is more reactive than bromine. Therefore, bromine cannot replace bromine.

In the second equation, the displacement is between hydrogen and aluminium. Hydrogen is lower in the activity series, this implies that aluminum will replace it.

5 0
3 years ago
Using the following reaction:
Romashka-Z-Leto [24]

Answer:

Mn is the oxidizing agent.

N is the reducing agent.

Explanation:

Hello!

In this case, according to the undergoing chemical reaction, it is seen that the manganese in KMnO4 has an oxidation state of 7+, in MnSO4 of 2+ and nitrogen in KNO2 is 3+ and in KNO3 is 5+; thus we have the following half-reactions:

Mn^{7+}+5e^-\rightarrow Mn^{2+}\\\\N^{3+}\rightarrow N^{5+}+2e^-

Thus, since manganese is undergoing a decrease in the oxidation state, we infer it is the oxidizing agent whereas nitrogen, undergoing an increase in the oxidation state is the reducing agent.

Best regards!

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Explanation:

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