Hi sweetie, hope this helps!
The more salt that is dissolved in the water, the less oxygen will be dissolved in it.
The higher the temperature of the water, the less oxygen will be dissolved it in.
Goodluck!,
Izzy
Which question the top part, middle or the 7 covalents?
Answer:
The estimated feed rate of logs is 14.3 logs/min.
Explanation:
The product of the process is 2000 tons/day of dry wood pulp, of 85 wt% of cellulose. That represents (2000*0.85)=1700 tons/day of cellulose.
That cellulose has to be feed by the wood chips, which had 47 wt% of cellulose in its composition. That means you need (1700/0.47)=3617 tons/day of wood chips to provide all that cellulose.
Th entering flow is wood chips with 45 wt% of water. This solution has an specific gravity of 0.640.
To know the specific gravity of the wood chips we have to write a volume balance. We also know that Mw=0.45*M and Mc=0.55*M.

The specific gravity of the wood chips is 0.494.
The average volume of a log is

The weight of one log is

To provide 3617 ton/day of wood chips, we need


The feed rate of logs is 14.3 logs/min.
Answer:
See notes on LeChatlier's Principle I gave you yesterday.
Explanation:
Remember chemical see-saw => Removing Fe⁺³ makes the reactant side of the see-saw lighter causing the balance to tilt right then shift left to establish a new equilibrium with new concentration values. Such would result in a decrease in FeSCN⁺² concentration and increases in Fe⁺³ and SCN⁻ concentrations to replace the original amount of ppt'd Fe⁺³. => Answer Choice 'B' ... Also, see attached => Concentration effects on stability of chemical equilibrium .
Answer is: the molecular formula is C₆H₁₀.
Chemical reaction: C₆Hₓ + yO₂ → 6CO₂ + x/2H₂O.
m(H₂O) = 0.9102; mass of the water.
n(H₂O) = m(H₂O) ÷ m(H₂O)
n(H₂O) = 0,9102 g ÷ 18 g/mol
n(H₂O) = 0,0505 mol.
From chemical reaction: n(H) = 2 · n(H₂O).
n(H) = 0.101 mol.
m(CO₂) = 2.668 g; mass of carbon dioxide.
n(CO₂) = 2.668 g ÷ 44 g/mol.
n(CO₂) = 0.0606 mol; amount of the substance.
n(CO₂) = n(C) = 0.0606 mol.
n(C) : n(H) = 0.606 mol : 0.101 mol.
n(C) : n(H) = 6 : 10; proportion of carbon and hydrogen atoms in cyclohexene.