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2 years ago

10

Select the structure that corresponds

1 answer:

Lostsunrise [7]2 years ago

8 0

Answer:

C. both

Explanation:

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You have the equations:

kari74 [83]

Answer:

the answer is 99.0kJ

Explanation:

I took the test in chemistry

7 0

3 years ago

How do absolute and apparent magnitude values compare for our sun? Why are the two values different for our sun?

Aliun [14]

The apparent brightness, or apparent magnitude, depends on the location of the observer.Different<span> observers will come up with a </span>different<span> measurement, depending on </span>their<span> locations and distance from the star. Stars that are closer to Earth, but fainter, </span>could<span> appear brighter than far more luminous ones that ...</span>

6 0

3 years ago

This is a group on elements with properties of both a metal and a nonmetal. Example: silicon, antimony, also known as a metalloi

tiny-mole [99]

These are metalloids. :)

8 0

3 years ago

At a certain temperature, 0.900 mol SO 3 is placed in a 2.00 L container. 2 SO 3 ( g ) − ⇀ ↽ − 2 SO 2 ( g ) + O 2 ( g ) At equil

puteri [66]

Answer: The value of $K_c$ is 0.0057

Explanation:

Initial moles of $SO_3$ = 0.900 mole

Volume of container = 2.00 L

Initial concentration of $SO_3=\frac{moles}{volume}=\frac{0.900moles}{2.00L}=0.450M$

equilibrium concentration of $O_2=\frac{moles}{volume}=\frac{0.110mole}{2.00L}=0.055M$ [/tex]

The given balanced equilibrium reaction is,

$2SO_3(g)\rightleftharpoons 2SO_2(g)+O_2(g)$

Initial conc. 0.450 M 0 0

At eqm. conc. (0.450 -2x) M (2x) M (x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[O_2][SO_2]^2}{[SO_3]^2}$

$K_c=\frac{x\times (2x)^2}{0.450-2x)^2}$

we are given : x = 0.055

Now put all the given values in this expression, we get :

$K_c=\frac{0.055\times (2\times 0.055)^2}{0.450-2\times 0.055)^2}$

$K_c=0.0057$

Thus the value of the equilibrium constant is 0.0057

3 0

4 years ago

The density of a pure substance is its mass per unit volume. The density of ethylene glycol has been measured to be 1097.gL. Cal

Svetlanka [38]

Answer: The mass of 405 mL of ethylene glycol is 444.3 g.

Explanation:

Density is defined as the mass contained per unit volume.

$Density=\frac{mass}{Volume}$

Given :

Density of the ethylene glycol= $1097g/L$

Volume of the ethylene glycol= $405ml$ = 0.405 L (1L=1000ml)

Mass of the ethylene glycol = ?

Putting in the values we get:

$1097g/L=\frac{x}{0.405L}$

$x=444.3g$

Thus the mass of 405 mL of ethylene glycol is 444.3 g

5 0

3 years ago