Answer:
Q = 2260.44 j
Explanation:
Given data:
Mass of ice = 18 g
Initial temperature = -10 °C
Final temperature = 20°C
Heat absorbed by ice = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = Final temperature - initial temperature
ΔT = 20°C - (-10°C)
ΔT = 30°C
Specific heat of water = 2.00 j/g.°C
Q = 18 g × 4.186 j/g.°C × 30°C
Q = 2260.44 j
Valency- it means the combing capacity if an element.
<span> radical- it is an atom, molecule, or ion that has unpaired valence electrons or an open electron shell.
</span>
Hope this helps! Also if it’s hard to read just look up “ what is a protein coat” pretty easy right?
According to Dalton's Law, in a mixture of non-reacting gasses, thetotal pressure<span> exerted is the sum of the </span>partial pressures<span> of the component gasses. In more complicated circumstances, equilibrium states come into effect, but fortunately for us, </span>oxygen<span> is non-reactive with </span>water vapor<span>.</span>
Answer:
-40 degress
Explanation:
To find the temperature when both are equal, we use an old algebra trick and just set ºF = ºC and solve one of the equations. So the temperature when both the Celsius and Fahrenheit scales are the same is -40 degrees.