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3 years ago

Boss tweed encourage his associates to work like a well oiled machine thus providing his workers with

Physics

2 answers:

Svetllana [295]3 years ago

4 0

An <em>analogy </em>is the answer

juin [17]3 years ago

3 0

Boss tweed encourage his associates to work like a well oiled machine thus providing his workers with benefits that encourages them to work like a well oiled machine. A well oiled machine means that it does not stop, its work is continuous and efficient.

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How is displacement different from distance?

Anni [7]

Answer:

i do belive its C

Explanation:

i remeber this question from somewhere also it makes the most sense

5 0

3 years ago

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6. Dentists use a soft, clay-like material to make a filling for a cavity. The filling stays soft under the

Mice21 [21]

Answer:

Ultraviolet light is a stronger type of light. The light the dentist uses is a softer light that is just used to help you see.

Explanation:

6 0

3 years ago

A light ray incident from medium 1 to medium 2, where n1>n2. When the incident angle exceed the critical angle ac, the refrac

vovikov84 [41]

Explanation:

(a)

Critical angle is the angle at the angle of refraction is 90°. After the critical angle, no refraction takes place.

Using Snell's law as:

$n_1\times {sin\theta_i}={n_2}\times{sin\theta_r}$

Where,

${\theta_i}$ is the angle of incidence

${\theta_r}$ is the angle of refraction = 90°

${n_2}$ is the refractive index of the refraction medium

${n_1}$ is the refractive index of the incidence medium

Thus,

$n_1\times {sin\ \theta_{critical}}={n_2}\times{sin\ 90^0}$

The formula for the calculation of critical angle is:

${sin\theta_{critical}}=\frac {n_2}{n_1}$

Where,

${\theta_{critical}}$ is the critical angle

(b)

No it cannot occur. It only occur when the light ray bends away from the normal which means that when it travels from denser to rarer medium.

7 0

3 years ago

If a current is two amps and the resistance is 3 ohms, how much voltage was needed?

Hunter-Best [27]

Answer:

6 V

Explanation:

We can solve the problem by using Ohm's law:

$V=RI$

where

V is the voltage in the circuit

R is the resistance

I is the current

In this problem, we know the current, $I=2 A$ , and the resistance, $R=3 \Omega$ , therefore we can find the voltage in the circuit:

$V=RI=(3 \Omega )(2 A)=6 V$

7 0

3 years ago

A beam of light traveling through a liquid (of index of refraction n1 = 1.47) is incident on a surface at an angle of θ1 = 59° w

frosja888 [35]

Answer:

(a) $n_{2} = \frac{n_{1}sin\theta_{1}}{sin\theta_{2}}$

(b) $n_{2} = 1.349$

(d) $v_{2} = 2.22\times 10^{8}\ m/s$

Solution:

As per the question:

Refractive index of medium 1, $n_{1} = 1.47$

Angle of refraction for medium 1, $\theta_{1} = 59^{\circ}$

Angle of refraction for medium 2, $\theta_{1} = 69^{\circ}$

Now,

(a) The expression for the refractive index of medium 2 is given by using Snell's law:

$n_{1}sin\theta_{1} = n_{2}sin\theta_{2}$

where

$n_{2}$ = Refractive Index of medium 2

Now,

$n_{2} = \frac{n_{1}sin\theta_{1}}{sin\theta_{2}}$

(b) The refractive index of medium 2 can be calculated by using the expression in part (a) as:

$n_{2} = \frac{1.47\times sin59^{\circ}}{sin69^{\circ}}$

$n_{2} = 1.349$

We know that:

$Refractive\ index,\ n = \frac{Speed\ of\ light\ in vacuum,\ c}{Speed\ of\ light\ in\ medium,\ v}$

Thus for medium 1

$n_{1} = \frac{c}{v_{1}$

$v_{1} = \frac{c}{n_{1} = \frac{3\times 10^{8}}{1.47} = 2.04\times 10^{8}\ m/s$

(d) To calculate the velocity of light in medium 2:

For medium 2:

$n_{2} = \frac{c}{v_{2}$

$v_{2} = \frac{c}{n_{1} = \frac{3\times 10^{8}}{1.349} = 2.22\times 10^{8}\ m/s$

5 0

3 years ago

Read 2 more answers