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3 years ago

A rectangular greenhouse has an area of 6480 square meters and a length of 120 meters. How many meters is it in width?

Mathematics

2 answers:

Crazy boy [7]3 years ago

8 0

A=LW

W=A/L, A=6480 and L=120 so

W=6480/120 m

W=54 m

bonufazy [111]3 years ago

3 0

Area is length x width. If the area is 6480, and you know the length, plug it into the formula to find the width.

120 x width = 6480

So, to solve, you would divide 6480 by 120 to find the width. 6480/120 = 54.

Therefore, the width is 54.

Comment under this post or message me for further help!

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Given:

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The ratio in which he point P divides the segment AB.

Solution:

Section formula: If a point divides a segment in m:n, then the coordinates of that point are,

$Point=\left(\dfrac{mx_2+nx_1}{m+n},\dfrac{my_2+ny_1}{m+n}\right)$

Let point P divides the segment AB in m:n. Then by using the section formula, we get

$\left(\dfrac{3}{4},\dfrac{5}{12}\right)=\left(\dfrac{m(2)+n(\dfrac{1}{2})}{m+n},\dfrac{m(-5)+n(\dfrac{3}{2})}{m+n}\right)$

$\left(\dfrac{3}{4},\dfrac{5}{12}\right)=\left(\dfrac{2m+\dfrac{n}{2}}{m+n},\dfrac{-5m+\dfrac{3n}{2}}{m+n}\right)$

On comparing both sides, we get

$\dfrac{3}{4}=\dfrac{2m+\dfrac{n}{2}}{m+n}$

$\dfrac{3}{4}(m+n)=\dfrac{4m+n}{2}$

Multiply both sides by 4.

$3(m+n)=2(4m+n)$

$3m+3n=8m+2n$

$3n-2n=8m-3m$

$n=5m$

It can be written as

$\dfrac{1}{5}=\dfrac{m}{n}$

$1:5=m:n$

Therefore, the point P divides the line segment AB in 1:5.

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