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OLga [1]
3 years ago
13

Se denomina asi al movimiento de particulas con carga eléctrica en determinada dirección.

Physics
1 answer:
andrey2020 [161]3 years ago
3 0

Answer:

si la. carga es positiva experimenta una fuerza en el sentido del campo

en cambio si la carga es negativa,experimenta una fuerza en sentido contrario al campo

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A sledge is pulled in a straight line by dogs, as shown. The dogs produce a total horizontal driving force of 600 N. The frictio
kifflom [539]

Answer:

F = 0 N

Explanation:

The direction of air resistance and frictional force will be same and opposite to the direction of the driving fore of dogs. Therefore, the resultant force can be given as follows:

resultant\ Force = F = Driving\ Force\ of\ Dogs - Frictional\ Force - Air\ Resistive\ Forcehere,

driving force of dogs = 600 N

Frictional Force = 150 N

Resultant Force = 450 N

Therefore,

F = 600\ N - 150\ N- 450\ N

<u>F = 0 N</u>

5 0
3 years ago
a cylindrical can of radius 200mm has liquid weighs 50kg. Find the height of liquid in cm in the can, if the density is 0.8g/cm3
anygoal [31]

density = mass/volume

50 kg to g

50*1000 = 50,000 grams

200 mm to cm

200*0.1 = 20 cm

Substitute: 0.8=50,000/volume of a cylinder

volume of cylinder= (pi)(r^2)(h)

volume of cylinder=(pi)(20^2)(h)

0.8=50,000/((pi)(20^2)(h))

0.8=50,000/400*pi*h

50,000/0.8=400*pi*h

62,500=400*pi*h

62,500/(400*pi)=h

h≈49.74 cm

4 0
3 years ago
What was one result of the second great awakening
Brrunno [24]
The membership rose among the baptist and methodists.
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4 years ago
A chemical property is a change in _____.
arsen [322]
A chemical property is a change in classification in matter I think
3 0
3 years ago
A hobby rocket reaches a height of 72.3 m and lands 111 m from the launch point with no air resistance. What was the angle of la
Deffense [45]

Answer:

The angle of launch is 52.49 Degree.

Explanation:

The Range R and Height H of a thrown object is calculated using the formula,

R=V₀² sin(2φ)/g

H=V₀²sin²(φ)/g

From these equations it can be written,

V₀²=R g/ sin(2φ)

V₀²=H g/ sin²(φ)

These values are equal so it can be written by equating these equations,

R g/sin(2φ)=H g/sin²(φ)

tan(φ)= 2H/R

Given H=72.3 m and R=111 m, the angle of launch is,

tan(φ)= 2*72.3/111

φ= 52.49 Degree.

Check out other solutions,

brainly.com/question/1495042

#SPJ10

7 0
2 years ago
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