Ask question

Ask question

All categories

3 years ago

11

The Milky Way galaxy is believed to be composed of over 200billion stars and to have a diameter of over 100000 light years. What

component of the Milky Way galaxy accounts for most of its mass

1 answer:

Makovka662 [10]3 years ago

5 0

Stars/black holes

Hope this Helps

You might be interested in

Calculate the velocity of the bicyclist between 0 and 3 seconds.

hoa [83]

Answer:

is there an equasion it gives you?

Explanation:

need a little more info.

4 0

3 years ago

A horizontal circular curve on a highway is designed for traffic moving at 60 km/h. If the radius of the curve is 150 m, and if

KengaRu [80]

Answer:

The value of the correct angle of banking for the road is $\theta = 67.76$ °

Explanation:

Given data

Velocity (v) = 60 $\frac{m}{s}$

Radius = 150 m

The velocity of the car in this case is given by

$v = \sqrt{r g \tan \theta}$

$v^{2} = r g \tan \theta$

$\tan \theta = \frac{v^{2} }{rg}$

Put all the values in above formula we get

$\tan \theta = \frac{60^{2} }{(150)(9.81)}$

$\tan \theta =$ 2.446

$\theta = 67.76$ °

Therefore the value of the correct angle of banking for the road is $\theta = 67.76$ °

4 0

3 years ago

The table below describes 100 offspring of the same two parents. What are the most likely genotypes of the parents?

mars1129 [50]

Answer:

im very con fused on what you mean by this

Explanation:

4 0

3 years ago

Read 2 more answers

Light is incident along the normal to face AB of a glass prism of refractive index 1.54. Find αmax, the largest value the angle

marusya05 [52]

To solve this problem it is necessary to use the concepts related to Snell's law.

Snell's law establishes that reflection is subject to

$n_1sin\theta_1 = n_2sin\theta_2$

Where,

$\theta =$ Angle between the normal surface at the point of contact

n = Indices of refraction for corresponding media

The total internal reflection would then be given by

$n_1 sin\theta_1 = n_2sin\theta_2$

$(1.54) sin\theta_1 = (1.33)sin(90)$

$sin\theta_1 = \frac{1.33}{1.54}$

$\theta = sin^{-1}(\frac{1.33}{1.54})$

$\theta = 59.72\°$

Therefore the $\alpha_{max}$ would be equal to

$\alpha = 90\°-\theta$

$\alpha = 90-59.72$

$\alpha = 30.27\°$

Therefore the largest value of the angle α is 30.27°

3 0

3 years ago

19 dm expressed in millimeters

alina1380 [7]

1900 millimeters thats wht i got

6 0

1 year ago