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Art [367]
3 years ago
11

Hurry up.

Physics
1 answer:
xenn [34]3 years ago
5 0

Answer:

expands

Explanation:

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When the mallet hits the ball with an action force, the ball exerts a reaction force on the mallet, as explained by ___
satela [25.4K]

Answer:

Newton's third law of motion.

Explanation:

Every action has an equal and opposite reaction.

4 0
3 years ago
Encontrar el peso de un elefante cuya masa es de 4500kg. Recordar que la gravedad es de 9.8m/s2
dusya [7]

la respuesta es 459.183673 kg s2 / m

7 0
3 years ago
Read 2 more answers
What is the pressure of a 300 lb. object on a 100 sq. in. area?
denis23 [38]

Answer:

D. 3 psi

Explanation:

Pressure is defined as force acting per unit area and is numerically expressed as:

P= \frac {F}{A}

where P represent pressure, F is force and A is area where the force acts. Substituting 300 lb for force and 100 sq.in for area then pressure,

P=\frac {300 lb}{100 in^{2}}= 3 \ psi

Therefore, from the choices given, option D, 3psi is the right choice.

3 0
3 years ago
After fixing a flat tire on a bicycle you give the wheel a spin. If its initial angular speed was 6.36 rad/s and it rotated 14.7
lesya692 [45]

To solve this problem we will apply the concepts related to the cinematic equations of angular motion. On these equations, angular acceleration is defined as the squared difference of angular velocity over twice the radial displacement. This is mathematically:

\alpha = \frac{\omega^2-\omega_0^2}{2\theta}

Our values are,

\text{Initial angular velocity} = \omega_0 =6.36 rad/s

\text{Final angular velocity} =  \omega =0

\text{Angular displacement} =  \theta = 14.7rev = 29.4\pi rad

Replacing,

\alpha = \frac{- 6.36^2}{29.4\pi}

\alpha = -0.43rad/s^2

Therefore the angular acceleration is -0.43rad/s^2

4 0
3 years ago
How fast must a 2.70-g ping-pong ball move in order to have the same kinetic energy as a 145-g baseball moving at 31.0 m/s
Helen [10]

Answer:

227 m/s

Explanation:

Kinetic energy formula:

  • \displaystyle \text{KE} = \frac{1}{2} mv^2
  • where m = mass of the object (kg)
  • and v = speed of the object (m/s)

Let's find the kinetic energy of the 145-g baseball moving at 31.0 m/s.

First convert the mass to kilograms:

  • 145-g → 0.145 kg

Plug known values into the KE formula.

  • \displaystyle \text{KE} = \frac{1}{2} (.145)(31.0)^2
  • \displaystyle \text{KE} = 69.6725 \ \text{J}

Now we want to find how fast a 2.70-g ping pong ball must move in order to achieve a kinetic energy of 69.6725 J.

First convert the mass to kilograms:

  • 2.70-g → 0.00270 kg

Plug known values into the KE formula.

  • \displaystyle 69.6725 = \frac{1}{2} (.00270)v^2
  • \displaystyle \frac{2(69.6725)}{.00270} =v^2
  • 57609.25926=v^2
  • v=227.1767137

The ping-pong ball must move at a speed of 227 m/s to achieve the same kinetic energy as the baseball.

4 0
3 years ago
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