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guapka [62]
3 years ago
14

A cube of wood 15.0 cm on each side is tied to the bottom of a tank filled with water to a depth of 50 cm. The tension in the st

ring is found to be 6.615 N. Please answer each of the following questions. Note: 1 atm = 1.013 x 105 Pa a) What is the density of the wood? b) What is the absolute pressure at the bottom of the tank.
Physics
1 answer:
Elina [12.6K]3 years ago
7 0

Answer:

(a). The density of the wood is  1479.48\times10^{2}\ Kg/m^3

(b). The absolute pressure at the bottom of the tank is 1.06200\times10^{5}\ Pa.

Explanation:

Given that,

Side of cube = 15.0 cm

Depth = 50 cm

Tension = 6.615 N

We need to calculate the volume of the wood

Using formula of volume

V = a^3

V=(15.0\times10^{-2})^3

V=0.003375\ m^3

We need to calculate the density of the wood

Using buoyant force

\rho_{w}gh=mg+T

\rho_{w}gh=\rho_{c}Vg+T

Put the value into the formula

\rho_{c}=\dfrac{\rho_{w}gh-T}{Vg}

Put the value into the formula

\rho_{c}=\dfrac{1000\times9.8\times50\times10^{-2}-6.615}{0.003375\times9.8}

\rho_{c}=1479.48\times10^{2}\ Kg/m^3

(b). We need to calculate the absolute pressure at the bottom of the tank

Using formula of absolute pressure

P=P_{atm}+\rho gh

Put the value into the formula

P=1.013\times10^{5}+1000\times9.8\times0.5

P=1.06200\times10^{5}\ Pa

Hence, (a). The density of the wood is  1479.48\times10^{2}\ Kg/m^3

(b). The absolute pressure at the bottom of the tank is 1.06200\times10^{5}\ Pa.

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