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Nataliya [291]
3 years ago
5

How does the direction of acceleration compare with the direction of the net force that produces it

Physics
1 answer:
Novay_Z [31]3 years ago
8 0

Answer:

Explanation:

The direction of the acceleration is in the same direction as the net force causing it.  F = ma is actually a vector equation in which f and a are both vectors and m is a scalar constant.

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Determine the force of gravitational attraction between the Earth and the moon. Their masses are 5.98 x 1024 kg and 7.26 x 1022
monitta

Answer:

F=1.95\times 10^{20}\ N

Explanation:

Mass of Earth, m_e=5.98 \times 10^{24}\ kg

Mass of Moon, m_m=7.26\times 10^{22}\ kg

The distance between Earth and the Moon is, d=384,400\ km

We need to find the force of gravitational attraction between the Earth and the moon. The force of gravity is given by :

F=G\dfrac{m_em_m}{r^2}\\\\F=6.67\times 10^{-11}\times \dfrac{5.98 \times 10^{24}\times 7.26\times 10^{22}}{(384400 \times 10^3)^2}\\\\F=1.95\times 10^{20}\ N

So, the required force is 1.95\times 10^{20}\ N.

4 0
3 years ago
Define the term potential energy of a body? <br> How is it measured
DENIUS [597]

Answer:

potential energy. noun. the energy of a body or system as a result of its position in an electric, magnetic, or gravitational field. It is measured in joules (SI units), electronvolts, ergs, etcSymbol: E p, V, U, φ Abbreviation: PE.

Explanation:

4 0
2 years ago
Read 2 more answers
Pedro is planning to model how changes in weather affect evaporation from lakes for his first experiment he wants to test how hu
Valentin [98]

Answer:

C. volume of water and temperature

Explanation:

a p e x

6 0
3 years ago
What is the kinetic energy of a 0.135 kg baseball thrown at 40 m/s
Ronch [10]
KE = 1/2 * m * v^2
KE = 1/2 * 0.135 * 40^2
KE = 1/2 * 0.135 * 1600
KE = 108 J
4 0
3 years ago
Helpp pls
Kipish [7]

Answer:

The intensity of the electric field is

|E|=10654.37 \:N/C

Explanation:

The electric field equation is given by:

|E|=k\frac{q}{d^{2}}

Where:

  • k is the Coulomb constant
  • q is the charge at 0.4100 m from the balloon
  • d is the distance from the charge to the balloon

As we need to find the electric field at the location of the balloon, we just need the charge equal to 1.99*10⁻⁷ C.

Then, let's use the equation written above.

|E|=(9*10^{9})\frac{1.99*10^{-7}}{0.41^{2}}

|E|=10654.37 \:N/C

I hope it helps you!

5 0
3 years ago
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