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Nataliya [291]
3 years ago
5

How does the direction of acceleration compare with the direction of the net force that produces it

Physics
1 answer:
Novay_Z [31]3 years ago
8 0

Answer:

Explanation:

The direction of the acceleration is in the same direction as the net force causing it.  F = ma is actually a vector equation in which f and a are both vectors and m is a scalar constant.

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A wheel with a tire mounted on it rotates at the constant rate of 2.73 revolutions per second. Find the radial acceleration of a
Lostsunrise [7]

Answer:

110.9 m/s²

Explanation:

Given:

Distance of the tack from the rotational axis (r) = 37.7 cm

Constant rate of rotation (N) = 2.73 revolutions per second

Now, we know that,

1 revolution = 2\pi radians

So, 2.73 revolutions = 2.73\times 2\pi=17.153\ radians

Therefore, the angular velocity of the tack is, \omega=17.153\ rad/s

Now, radial acceleration of the tack is given as:

a_r=\omega^2 r

Plug in the given values and solve for a_r. This gives,

a_r=(17.153\ rad/s)^2\times 37.7\ cm\\a_r=294.225\times 37.7\ cm/s^2\\a_r=11092.28\ cm/s^2\\a_r=110.9\ m/s^2\ \ \ \ \ \ \ [1\ cm = 0.01\ m]

Therefore, the radial acceleration of the tack is 110.9 m/s².

4 0
3 years ago
Two loudspeakers are about 10 m apart in the front of a large classroom. if either speaker plays a pure tone at a single frequen
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The observed differences in amplitudes are due to interference between the sound waves. The decrease in amplitude is due to destructive interference of the waves and the increase in amplitude is due to constructive interference.
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A basketball is tossed up at an initial speed of 20 m/s.
qwelly [4]

Gravity slows the upward speed of any rising object by 9.8 m/s every second.

If the ball is tossed upward at 20 m/s, then it's at the top of its arc and its speed has dwindled to zero in (20/9.8) = 2.04 seconds.

During that time, its starting speed is 20 m/s and its ending speed is zero, so its AVERAGE speed all the way up is (1/2) (20 + 0)  =  10 m/s .

Sailing upward for 2.04 seconds at an average speed of 10 m/s, the ball rises to (2.04 x 10)  =  <em>20.4 meters.</em>

4 0
3 years ago
the gasoline in a car does 40000 j of work on a car and generates a constant force of 20 n. how far did the car go?
NikAS [45]

     Work  =  (force) x (distance)

     40,000 J  =  (20 N) x (distance)

     Distance  =  (40,000 J) / (20 N)

                    =    2,000 meters

                    =     2 kilometers.

(20 N is not a huge force when it's being used to move a car.
It's only about  4.5 pounds.) 
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What can iron filings sprinkled on a piece of paper demonstrate?
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<span>c the pattern of the magnetic fields lines</span>
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