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MA_775_DIABLO [31]

3 years ago

7

How does electroscope detect type of charge ?

1 answer:

Shtirlitz [24]3 years ago

6 0

Answer:

An electroscope is an early scientific instrument used to detect the presence of electric charge on a body. It detects charge by the movement of a test object due to the Coulomb electrostatic force on it. The amount of charge on an object is proportional to its voltage.

Explanation:

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What part of the atmosphere contains dust, water vapor, and 75% of all gases

Alexeev081 [22]

Answer:

Troposphere

Explanation:

Our atmosphere yay

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3 years ago

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Mrs. Howel, the principal, can expel a student for misconduct. In terms of social pressure, Mrs. Howel is capable of eliciting

dybincka [34]

The answer would be D)Apathy

8 0

3 years ago

Lacie kicks a football from ground level at a velocity of 13.9 m/s and at an angle of 25.0° to the ground. How long will the bal

Step2247 [10]

Answer:

T = 1.2 s

T = 15.1 m = 15 m

Explanation:

This is a case of projectile motion:

TOTAL TIME OF FLIGHT:

The formula for total time of flight in projectile motion is:

T = 2 V₀ Sinθ/g

where,

T = Total Time of Flight = ?

V₀ = Launch Speed = 13.9 m/s

θ = Launch Angle = 25°

g = 9.8 m/s²

Therefore,

T = (2)(13.9 m/s)(Sin 25°)/(9.8 m/s²)

<u>T = 1.2 s</u>

<u></u>

RANGE OF BALL:

The formula for range in projectile motion is:

R = V₀² Sin2θ/g

where,

R = Horizontal Distance Covered by ball = ?

Therefore,

T = (13.9 m/s)²(Sin 2*25°)/(9.8 m/s²)

<u>T = 15.1 m = 15 m</u>

4 0

3 years ago

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An 18kg block moving at 6 m/s has kinetic energy of

sergey [27]

½ × 18 × 6² = 324 J

hope that helps^^

6 0

3 years ago

Diagram shows the velocity time graph for a particle moving in 16 seconds.

Leya [2.2K]

Answer:

The detailed calculations are shown below;

Explanation:

a)The maximum acceleration of the particle:

It is seen that the maximum change in velocity is at the time between 8s to 10s.

Maximum acceleration: $\frac{V}{t}$

= $\frac{20}{2}$

= 10 m/ $s^{2}$

b) The deceleration of the particle

The velocity of particle is decreased after 10s so,

deceleration = - $\frac{40}{6}$

= - 6.67 m/ $s^{2}$

c)The total distance traveled by the particle = Area under the curve

= $\frac{1}{2}$ * 4*20 + 4*20 + $\frac{1}{2}$ * 2*20+ 2*20+ $\frac{1}{2}$ * 40*16

= 290 m

d)The average velocity of the particle = $\frac{Area under the curve}{Total time}$

= $\frac{290}{16}$

= 18.12 m/s

3 0

3 years ago