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Naya [18.7K]
3 years ago
10

Approximate the field by treating the disk as a +6.1 C point charge at a distance of 21 cm Answer in units of N/C.

Physics
1 answer:
DaniilM [7]3 years ago
7 0

Answer:

Electric field, E=1.24\times 10^{12}\ N/C

Explanation:

It is given that,

Charge, Q = +6.1 C

Distance, r = 21 cm = 0.21 m

We need to find the electric field. It is given by :

E=k\dfrac{Q}{r^2}

E=9\times 10^9\times \dfrac{6.1}{(0.21)^2}

E=1.24\times 10^{12}\ N/C

So, the electric field at this distance is 1.24\times 10^{12}\ N/C. Hence, this is the required solution.

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What formal regions are located in the western hemisphere
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Answer: Part of Europe, part of Africa, part of Antarctic and the entire America.

Explanation: Western hemisphere or west hemisphere encompasses all regions located west of the longitude 0 °, or meridian of Greenwich.

The formal regions located in the western hemisphere is Europe, Africa, Antarctic and America.

4 0
3 years ago
Explain how pressure can be used to<br> change the state of matter
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Physical conditions like temperature and pressure affect state of matter. ... When the pressure exerted on a substance increases, it can cause the substance to condense. Decreasing pressure can cause it to vaporize. For some types of rock, decreasing pressure can also cause them to melt.

7 0
3 years ago
(b) Suppose oil spills from a ruptured tanker and spreads in a circular pattern. If the radius of the oil spill increases at a c
andreyandreev [35.5K]

Answer:

\frac{dA}{dt} \approx 245.044\,\frac{m^{2}}{s}

Explanation:

The formula for the surface of the circle is:

A(r) = \pi\cdot r^{2}

The rate of change of the spill area is obtained by deriving the previous formula in terms of time:

\frac{dA}{dt} = 2\pi\cdot r\cdot \frac{dr}{dt}

Finally, variables are replaced by known data:

\frac{dA}{dt} = 2\pi\cdot (39\,m)\cdot (1\,\frac{m}{s} )

\frac{dA}{dt} \approx 245.044\,\frac{m^{2}}{s}

4 0
4 years ago
Read 2 more answers
Given the recent evidence suggesting that species change due to a certain genetic variations, what would be true?
boyakko [2]

Answer:

c) mutation and natural selection both cause changes in a population

Explanation:

Hope it help

Mark me as brainliest

6 0
3 years ago
The percentage of fe in an iron ii sample was determined by redox titration with cr2o7 calculate the molarity of the standard k2
Archy [21]

The molarity is 0.018M and the percentage is 8.46%.

Net ionic reaction is

$\mathrm{Cr} 2 \mathrm{O}^{2-}+6 \mathrm{Fe}^{2+}+14 \mathrm{H}^{+} \rightarrow 6 \mathrm{Fe}^{3+}+2 \mathrm{Cr}^{3+}+7 \mathrm{H} 2 \mathrm{O}$

$1 \mathrm{~mol}$ of $\mathrm{Cr} 2 \mathrm{O} 7(-2)$ reacts with $6 \mathrm{~mol}$of $\mathrm{Fe}(2+)$ to form $6 \mathrm{~mol}$of $\mathrm{Fe}(3+)$ and $2 \mathrm{~mol}$ of $\mathrm{Cr}(3+)$

Find molarity of $\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7$

Molarity = moles of$\mathrm{K} 2 \mathrm{Cr} 207 /$ Volume of $\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7(\mathrm{~L}$ )

Moles of $\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7$ = grams of $\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7 /$ molar mass of $\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7$

$=1.2275 \mathrm{~g} / 294.19 \mathrm{~mol}=0.0042 \mathrm{~g} / \mathrm{mol}$

Molarity of $\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7=$ moles of $\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7$/ Volume of $\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7$(L)

$=0.0042 \mathrm{~g} / \mathrm{mol} / 0.250 \mathrm{~L}=0.017 \mathrm{M}$

Find molarity of $\mathrm{Fe}$ (II)

Molarity of $\mathrm{Fe}(\mathrm{II})=6 \times$molarity of $\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7 \times$volume of $\mathrm{K} 2 \mathrm{Cr} 2 \mathrm{O} 7 /$volume of $\mathrm{Fe}$ (II)

$=6 \times 0.017 \mathrm{M} \times 0.03598 \mathrm{~L} / 0.200 \mathrm{~L}$

$=0.018 \mathrm{M}$

Find moles of $\mathrm{Fe}(\mathrm{II})$

Moles of \mathrm{Fe}($ II) =molarity of $\mathrm{Fe}$ (II) $\times$ volume of $\mathrm{Fe}$ (II)

=0.018 \mathrm{M} \times 0.200 \mathrm{~L}=0.004 \mathrm{~mol}

Find mass of Fe(II)

Mass of \mathrm{Fe}( II )= moles of \mathrm{Fe}( II) \times molar mass of $\mathrm{Fe}(\mathrm{II})$

$=0.004 \mathrm{~mol} \times 55.85 \mathrm{~g} / \mathrm{mol}$

$=0.205 \mathrm{~g}$

Find $\% \mathrm{Fe}(\mathrm{II})$ in unknown sample

$$\begin{aligned}\% \mathrm{Fe} &=(\text { mass of } \mathrm{Fe} / \text { weight of unknown sample }) \times 100 \\&=(0.205 \mathrm{~g} / 2.4234 \mathrm{~g}) \times 100 \\&=8.46 \%\end{aligned}$$

  • Molarity is the concentration of a solution expressed as the number of moles of solute dissolved in each liter of solution.
  • concentration is the amount of a substance per defined space. Concentration usually is expressed in terms of mass per unit volume.

To know more about  MOLARITY    visit : brainly.com/question/8732513

#SPJ4

7 0
2 years ago
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