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andriy [413]
3 years ago
14

two pulse waves a and b arrive at a point in a medium simustaneously. if the amplitude of wave a is 35 units the amplitude of wa

ve b is 41 units and the two waves are in phase what is the resultant wave amplitude at the point of interference
Physics
1 answer:
Shalnov [3]3 years ago
3 0
It depends on the type of interference.
For constructive interference, add the amplitudes to get |35 + 41| = 76 units.
For destructive, subtract them |35 - 41| = 6 units
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Water is pumped from a reservoir to a tank suspended 12 m above the reservoir. The water flows through the same size pipe throug
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Explanation:

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If the speed of an object is doubled, what happens to its kinetic energy?
asambeis [7]

Answer:

Kinetic energy is energy of motion. Doubling the speed will quadruple the kinetic energy. The relationship between speed and kinetic energy is: This means that the factor by which kinetic energy increases is the square of the factor by which speed or velocity increases for a given object.

Explanation:

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3 years ago
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2. If a rock fell down a cliff and hit the bottom of the ravine at 4 seconds, how fast was the rock
Iteru [2.4K]

Answer: -39.2 m/s or 39.2 m/s directed downwards

Explanation:

This situation is a good example of Free Fall, where the main condition is that the initial velocity must be zero V_{o}=0, and the acceleration is constant (acceleration due gravity).

So, in order to calculate the final velocity V of the rock just at the moment it hitsthe bottom of the cliff, we will use the following equation:

V={V_{o}}^{2}+gt

Where:

g=-9.8 m/s^{2} is the acceleration due gravity (directed downwards)

t=4 s is the time it takes to the rock to fall down the cliff

V=(-9.8 m/s^{2})(4 s)

V=-39.2 m/s This is the rock's final velocity and its negative sign indicates it is directed downwards

6 0
3 years ago
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Given vectors D (3.00 m, 315 degrees wrt x-axis) and E (4.50 m, 53.0 degrees wrt x-axis), find the resultant R= D + E. (a) Write
Eva8 [605]

Answer:

  • R = ( 4.831 m , 1.469 m )
  • Magnitude of R = 5.049 m
  • Direction of R relative to the x axis= 16°54'33'

Explanation:

Knowing the magnitude and directions relative to the x axis, we can find the Cartesian representation of the vectors using the formula

\vec{A}= | \vec{A} | \ ( \ cos(\theta) \ , \ sin (\theta) \ )

where | \vec{A} | its the magnitude and θ.

So, for our vectors, we will have:

\vec{D}= 3.00 m \ ( \ cos(315) \ , \ sin (315) \ )

\vec{D}=  ( 2.121 m , -2.121 m )

and

\vec{E}= 4.50 m \ ( \ cos(53.0) \ , \ sin (53.0) \ )

\vec{E}= ( 2.71 m , 3.59 m )

Now, we can take the sum of the vectors

\vec{R} = \vec{D} + \vec{E}

\vec{R} = ( 2.121 \ m , -2.121 \ m ) + ( 2.71 \ m , 3.59 \ m )

\vec{R} = ( 2.121 \ m  + 2.71 \ m , -2.121 \ m + 3.59 \ m )

\vec{R} = ( 4.831 \ m , 1.469 \ m )

This is R in Cartesian representation, now, to find the magnitude we can use the Pythagorean theorem

|\vec{R}| = \sqrt{R_x^2 + R_y^2}

|\vec{R}| = \sqrt{(4.831 m)^2 + (1.469 m)^2}

|\vec{R}| = \sqrt{23.338 m^2 + 2.158 m^2}

|\vec{R}| = \sqrt{25.496 m^2}

|\vec{R}| = 5.049 m

To find the direction, we can use

\theta = arctan(\frac{R_y}{R_x})

\theta = arctan(\frac{1.469 \ m}{4.831 \ m})

\theta = arctan(0.304)

\theta = 16\°54'33''

As we are in the first quadrant, this is relative to the x axis.

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