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Evgesh-ka [11]
3 years ago
14

Need help with this one! Thank you xoxo!

Physics
2 answers:
kogti [31]3 years ago
7 0

The answer is Electron Attraction

stellarik [79]3 years ago
3 0

Answer:

it's electron attraction

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If the thrower takes 0.90 s to complete one revolution, starting from rest, what will be the speed of the discus at release?
Marysya12 [62]
Ω₀ = the initial angular velocity (from rest)
t = 0.9 s, time for a revolution
θ = 2π rad, the angular distance traveled

Let
α =  the angular acceleration
ω =  the final angular velocity

The angular rotation obeys the equation
(1/2)*(α rad/s²)*(0.9 s)² = (2π rad)
α = 15.514 rad/s²

The final angular velocity is
ω = (15.514 rad/s²)*(0.9 s) = 13.963 rad/s

If the thrower's arm is r meters long, the tangential velocity of release will be 
v = 13.963r m/s

Answer: 13.963 rad/s

8 0
3 years ago
what will be the focal lenght of a combined lens made by contact of two lenses of power +3D and -2D.​
4vir4ik [10]
  • P_1=+3D
  • P_2=-2D

\\ \bull\tt\dashrightarrow P=P_1+P_2

\\ \bull\tt\dashrightarrow P=+3D-2D=+1D

Now

\\ \bull\tt\dashrightarrow f=\dfrac{1}{P}

\\ \bull\tt\dashrightarrow f=\dfrac{1}{1}

\\ \bull\tt\dashrightarrow f=1m

3 0
2 years ago
A 0.144-kg baseball is moving toward home plate with a speed of 43 m/s when
algol [13]
I would say 648858. bc yes
4 0
3 years ago
John argues that energy is not conserved because when someone presses the brakes in a moving car, kinetic energy is lost. What s
babunello [35]
kinetic energy is converted into elastic potential energy stored in the brakes.
7 0
3 years ago
Consider a 2250-lb automobile clocked by law-enforcement radar at a speed of 85.5 mph (miles/hour). if the position of the car i
Korvikt [17]

As per law of Heisenberg uncertainty law

product of uncertainty in position and uncertainty in momentum will be constant

\Delta x . \Delta P = \frac{h}{4\pi}

\Delta x . m \Delta v = \frac{h}{4\pi}

now plug in all data

(5\times 0.3048). (2250 \times 0.454) \Delta v = \frac{6.6 \times 10^{-34}}{4\pi}

\Delta v = 3.37 \times 10^{-38} m/s

So above is the uncertainty in velocity of the object

4 0
3 years ago
Read 2 more answers
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