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Dafna1 [17]
3 years ago
12

If the speed of an object is unchanging, then what must be true?

Physics
2 answers:
Kazeer [188]3 years ago
7 0

If the speed of an object is unchanging, then the object is traveling at a <em>constant speed</em>.

"Unchanging" and "constant" mean the same thing.

lutik1710 [3]3 years ago
3 0

Answer:

If the speed of an object is unchanging it means that it's traveling at a constant speed.

If the speed of the object increases or decreases it means that the speed is changing. That's why those options are not valid.

The average speed implies that the speed changes over time, but just the average remains the same. That's why this option is not valid.

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4 years ago
Light-rail passenger trains that provide transportation within and between cities speed up and slow down with a nearly constant
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3 years ago
In a machining operation that approximates orthogonal cutting, the cutting tool has a rake angle =100 . The chip thickness ratio
Rudik [331]

Answer:

The percentage of the total energy dissipated into shear plane is 89.46%.

Explanation:

Given that,

Rake angle = 10°

Thickness ratio= 0.5

Cutting Force = 400 N

Thrust force = 200 N

Speed =3 m/s

Suppose the shear force is 345.21 N.

We need to calculate the shear plane angle

Using formula shear angle

\tan\phi=\dfrac{r\cos\alpha}{1-r\sin\alpha}

Put the value in to the formula

\tan\phi=\dfrac{0.5\cos10}{1-0.5\sin10}

\tan\phi=0.539

\phi=\tan^{-1}(0.539)

\phi=28.32^{\circ}

We need to calculate the shear velocity

Using formula of shear velocity

v_{2}=\dfrac{v\cos\alpha}{\cos(\phi-\alpha)}

Put the value into the formula

v_{2}=\dfrac{3\times\cos10}{\cos(28.32-10)}

v_{2}=3.11\ m/s

We need to calculate the percentage of the total energy dissipated into shear plane

Using formula of energy dissipated

\%d=\dfrac{P_{s}}{P}\times100

\%d=\dfrac{F_{s}\times v_{c}}{F_{c}\times v}\times100

Put the value into the formula

\%d=\dfrac{345.21\times3.11}{400\times3}\times100

d=89.46\%

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6 0
3 years ago
How do you measure the amplitude of a longitudinal wave?
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4 years ago
On isolated ground receptacles, the metal yoke ____ integrally bonded to the equipment grounding terminal of the receptacle.
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On isolated ground receptacles, the metal yoke is not allowed to be integrally bonded to the equipment grounding terminal of the receptacle.

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Learn more about  grounding conductors here brainly.com/question/14886979

#SPJ4.

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