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blagie [28]
4 years ago
7

Is CO, an air pollutant? How does it differ from other emissions resulting from the combustion of fossil fuels?

Engineering
1 answer:
Drupady [299]4 years ago
4 0

Answer:

Explanation:

CO, carbon monoxide is a toxic gas. It casues asphixiation on people and animals by interfering with hemoglobin, not allowing blood to transport oxygen to the cells in the body.

The normal emissions resulting from the combustion  of fussil fuels are CO2 (carbon dioxide) and H2O (water). Carbon monoxide is formed by an incomplete combustion of fossil fuels or carbon containing fuels in general, this not only produces toxic gas, but also is an inefficient combustion that wastes energy.

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Difference between velocity profile and velocity distribution​
Irina18 [472]

Answer:

Profile is a graphical representation of velocity distribution

7 0
3 years ago
A 2 m3 insulated rigid tank contains 3 kg of nitrogen at 90 kPa. Now work is done on the system until the pressure in the tank r
Nutka1998 [239]

Answer: \Delta S = 1.47kJ/K

Explanation: <u>Entropy</u> is the measure of a system's molecular disorder, i.e, the unuseful work a system does.

The nitrogen gas in the insulated tank can be described as an ideal gas, so it can be used the related formulas.

For the entropy, the ratio of initial and final temperatures is needed and as volume is constant, we use:

\frac{P_{1}}{T_{1}} =\frac{P_{2}}{T_{2}}

\frac{P_{2}}{P_{1}} =\frac{T_{2}}{T_{1}}

\frac{T_{2}}{T_{1}} =\frac{175}{90}

\frac{T_{2}}{T_{1}} =1.94

<u>Specific</u> <u>Heat</u> is the quantity of heat required to increase the temperature 1 degree of a unit mass of a substance. Specific heat of nitrogen at constant volume is c_{v}= 0.743kJ/kg.K

The change in entropy is calculated by

\Delta S= m[c_{v}ln(\frac{T_{2}}{T_{1}})-Rln(\frac{V_{2}}{V_{1}} )]

For the nitrogen insulated in a rigid tank:

\Delta S= m[c_{v}ln(\frac{T_{2}}{T_{1}})]

Substituing:

\Delta S= 3[0.743ln(1.94)]

\Delta S= 1.47

The entropy change of nitrogen in an insulated rigid tank is 1.47kJ/K

6 0
3 years ago
Which of the following Components Can't. be used as an amplifier Anless its Control electrode Conducts a Current? a) Ann-Channel
Nimfa-mama [501]

Answer:

d) A mosfet

Explanation:

MOSFET is the most common type of insulated gate Field Effect Transistor (FET),  used in electronic circuits and it stands for Metal Oxide Semiconductor Field Effect Transistor.

To configure MOSFET to act as an amplifier, a small AC signal is applied,   which is superimposed on to DC bias at the gate input, then the MOSFET will act as a linear amplifier.

Therefore, the correct option is (d) A mosfet

4 0
3 years ago
Scissors is to cut as?​
lidiya [134]

Answer:

yes...? uhm I don't know what this means

6 0
3 years ago
A thick spherical pressure vessel of inner radius 150 mm is subjected to maximum an internal pressure of 80 MPa. Calculate its w
ivann1987 [24]

Answer:

by principal stress theory

t = 20.226

by total strain theory

t = 20.36

Explanation:

given data

internal radius r_{1} = 150 mm

pressure p = 80 MPa

yield strength = 300 MPa

poisson's ratio = 0.3

a) by principal stress theory

thickness can be obtained as t

t  = r_{1}\left [ (\frac{\sigma _{y} +p}{\sigma _{y} - 0.5p})^{1/3}-1 \right ]

t = = 150\left [ (\frac{300 +80}{300-0.5*80})^{1/3}-1 \right ]

t = 20.226

b) by total strain theory

m =\frac{\sigma _{y}}{p}

m = \frac{300}{80} = 3.75

we know that

K = \frac{r_{2}}{r_{1} }

\frac{K^{3}+1}{K^{3}-1}= \frac{-2\mu +\sqrt{4\mu^{2}-2(1-\mu)(1-m^{^{2}}))}}{1-\mu}

\frac{K^{3}+1}{K^{3}-1}= \frac{-2*0.3 +\sqrt{4*0.3^{2}-2(1-0.3)(1-3.75^{^{2}}))}}{1-0.3}

\frac{K^{3}+1}{K^{3}-1}= 5.3

k = 1.13

1.13 = \frac{r_{2}}{150 }

r_{2} = 170.36 mm

t = r_{2}-r_{1}

t = 170.36 - 150

t = 20.36

5 0
4 years ago
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