Answer:
attached below
Explanation:
an 8 N weight is placed at one end of a meterstick. a 10N weight is placed at the other end. where should the fulcrum be placed
1 answer:
<h3><u>The fulcrum should be placed 0.44 from the 12 N weight or 0.56 m from the 8 N weight.</u></h3>
</h3>
</h3>
Explanation:
<h2>Given:</h2> = 8 N
= 10 N
Since the meter stick has a length of 1 m, and
Let = x
Let = 1 - x
Where should the fulcrum be placed to have the meterstick balanced?
<h2>Equation:</h2>For the system to be balanced, the product of the weight and distance of the objects on opposite sides should be equal. This is is shown by the equation:
where: w - weight
d - distance from the fulcrum
<h2>Solution:</h2>Substituting the value of and
in the formula,
(8 N)(x) = (10 N)(1 m - x)
x(8 N) = (10 N)m - x(10 N)
x(8 N) + x(10 N) = (10 N) m
x(18 N) = 10 N
x =
x = 0.56
<h3>Solve for = x
= 0.56 m
= 1 m - x
= 1 m - 0.56 m
= 0.44 m
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Hello, because there is not a circuit I'll explain the voltage divider and make an exercise, this way you can solve the problem using the method described here.
Answer with explanation:
A voltage divider uses the voltage distribution among components to find a voltage in a specific element of the circuit. If we have a source V1 connected to impedances Z1 and Z2 in series, we can use a voltage divider to find the voltage across Z1 or Z2 base on their value and the input voltage.
VZ1 = V1*Z1/(Z1+Z2)
VZ2 = V1*Z2/(Z1+Z2)
In the image, to find the voltage Vo across R2 we apply the following equation: Vo = (V1*R2)/(R1+R2).
To solve the exercise in the other image, we need to apply a voltage divider twice:
In-circuit 1 we are asked to find the voltage VAB that falls on R2 and R3 (the same voltage for both resistances because are in parallel), to do so we use a voltage divider using V1, R1 and RT where RT is the equivalent resistance RT = R2//R3 + R4, therefore, for circuit two VAC = (V1*R1)/(R1+RT). After finding VAC we apply voltage divider again to find VAB, see circuit 3, to do so we apply VAB = (VAC*R2//R3)/(R2//R3 + R4) = (VAC*R2//R3)/(RT)
