Ask question

Ask question

All categories

2 years ago

11

A three-point bending test is performed on a glass specimen having a rectangular cross section of height 5.3 mm and width 11.6 m

m; the distance between support points is 50 mm.
Required:
a. Calculate the flexural strength (in MPa) if the load at fracture is 283 N. (Round up the final number to integer-no decimal please.)
b. What is the deflection, Δy=__________ mm, for a load of 265 N if the elastic modulus if the glass is 66 GPa?

1 answer:

wolverine [178]2 years ago

4 0

Answer:

a) 65.139 MPa

b) 17490 GPa

Explanation:

a) calculate the flexural strength

we now that for a three-point bending test the bending moment will occur at the midsection

Max stress ( flexural strength ) = MY / I

Max stress can be expressed as ; 3/2 * ( F*l / b*d^2 ) ------- ( 1 )

F ( load at fracture ) = 283

l (distance between support point ) = 50

b = 11.6

d = 5.3

substitute given data into equation 1 above

= 3/2 * (( 283 * 50) /( 11.6 * 5.3^2) )

= 3/2 * ( 14150 / 325.844 )

= 3/2 * 43.425 = 65.139 MPa

B ) Determine deflection ( Δ y )

load = 265 N

elastic modulus = 66 GPa

elastic modulus = tensile stress / tensile strain

Tensile stress = Δ y

strain = load = 66 GPa

therefore Δ y = 265 * 66 = 17490 GPa

You might be interested in

What is the sun's degree angle in the sky in summer and in winter?

Vladimir [108]

Answer:

At the time of the summer or winter solstices, the Sun is 23.44° degrees above or below the horizon, respectively, irrespective of time of day.

Explanation:

6 0

2 years ago

Force = 33 newtons

kicyunya [14]

Answer:

answer

Explanation:

4 0

2 years ago

Una frase de: ama la vida quien___________________________________

TEA [102]

Answer:

A phrase from: who loves life

Explanation:

5 0

2 years ago

The sum ofall microscopic forms of energy of a system is quantified as flow energy. a)True b) False

Sliva [168]

Answer: b) False

Explanation: Microscopic energy is the the energy that is based on the molecular level in a particular energy system. Microscopic energy basically comprise with tiny particles like atoms and molecules .The sum of all microscopic form of energy e together make the internal energy .Therefore, the statement given is false because the sum of all the microscopic forms of energy of a system is quantified as internal energy not flow energy.

3 0

3 years ago

Instead of running blood through a single straight vessel for a distance of 2 mm, one mammalian species uses an array of 100 tin

Marina CMI [18]

Solution:

Given that :

Volume flow is, $Q_1 = 1000 \ mm^3/s$

So, $Q_2= \frac{1000}{100}=10 \ mm^3/s$

Therefore, the equation of a single straight vessel is given by

$F_{f_1}=\frac{8flQ_1^2}{\pi^2gd_1^5}$ ......................(i)

So there are 100 similar parallel pipes of the same cross section. Therefore, the equation for the area is

$\frac{\pi d_1^2}{4}=1000 \times\frac{\pi d_2^2}{4}$

or $d_1=10 \ d_2$

Now for parallel pipes

$H_{f_2}= (H_{f_2})_1= (H_{f_2})_2= .... = = (H_{f_2})_{10}=\frac{8flQ_2^2}{\pi^2 gd_2^5}$ ...........(ii)

Solving the equations (i) and (ii),

$\frac{H_{f_1}}{H_{f_2}}=\frac{\frac{8flQ_1^2}{\pi^2 gd_1^5}}{\frac{8flQ_2^2}{\pi^2 gd_2^5}}$

$=\frac{Q_1^2}{Q_2^2}\times \frac{d_2^5}{d_1^5}$

$=\frac{(1000)^2}{(10)^2}\times \frac{d_2^5}{(10d_2)^5}$

$=\frac{10^6}{10^7}$

Therefore,

$\frac{H_{f_1}}{H_{f_2}}=\frac{1}{10}$

or $H_{f_2}=10 \ H_{f_1}$

Thus the answer is option A). 10

7 0

3 years ago