All categories

2 years ago

What is the hardest part of thermodynamics?

Engineering

1 answer:

liubo4ka [24]2 years ago

6 0

Answer:

I would say that the hardest part about learning Thermodynamics is the generality and abstractness of it all.

Explanation:

You might be interested in

Three natural materials that were used by early man as roof covering

olga55 [171]

Explanation:

animal parts, wood, rock, and clay

8 0

2 years ago

Read 2 more answers

If you measured a pressure difference of 50 mm of mercury across a pitot tube placed in a wind tunnel with 200 mm diameter, what

mart [117]

Answer:

V=33.66 m/s

$Re=448.8\times 10^6$

Re>4000, The flow is turbulent flow.

Explanation:

Given that

Pressure difference = 50 mm of Hg

We know that density of Hg=136000 $Kg/m^3$

ΔP= 13.6 x 1000 x 0.05 Pa

ΔP=680 Pa

Diameter of tunnel = 200 mm

Property of air at 25°C

ρ=1.2 $Kg/m^3$

Dynamic viscosity

$\mu =1.8\times 10^{-8}\ Pa.s$

Velocity of fluid given as

$V=\sqrt{\dfrac{2\Delta P}{\rho_{air}}}$

$V=\sqrt{\dfrac{2\times 680}{1.2}}$

V=33.66 m/s

Reynolds number

$Re=\dfrac{\rho _{air}Vd}{\mu }$

$Re=\dfrac{1.2\times 33.66\times 0.2}{1.8\times 10^{-8}}$

$Re=448.8\times 10^6$

Re>4000,So the flow is turbulent flow.

4 0

3 years ago

Determine the resistance of 3km of copper having a diameter of 0,65mm if the resistivity of copper is 1,7x10^8

LUCKY_DIMON [66]

Answer:

Resistance of copper = 1.54 * 10^18 Ohms

Explanation:

<u>Given the following data;</u>

Length of copper, L = 3 kilometers to meters = 3 * 1000 = 3000 m

Resistivity, P = 1.7 * 10^8 Ωm

Diameter = 0.65 millimeters to meters = 0.65/1000 = 0.00065 m

$Radius, r = \frac {diameter}{2}$

$Radius = \frac {0.00065}{2}$

Radius = 0.000325 m

To find the resistance;

Mathematically, resistance is given by the formula;

$Resistance = P \frac {L}{A}$

Where;

P is the resistivity of the material.
L is the length of the material.
A is the cross-sectional area of the material.

First of all, we would find the cross-sectional area of copper.

Area of circle = πr²

Substituting into the equation, we have;

Area = 3.142 * (0.000325)²

Area = 3.142 * 1.05625 × 10^-7

Area = 3.32 × 10^-7 m²

Now, to find the resistance of copper;

$Resistance = 1.7 * 10^{8} \frac {3000}{3.32 * 10^{-7}}$

$Resistance = 1.7 * 10^{8} * 903614.46$

<em>Resistance = 1.54 * 10^18 Ohms </em>

3 0

2 years ago

A magnesium–lead alloy of mass 7.5 kg consists of a solid α phase that has a composition just slightly below the solubility limi

NARA [144]

Answer:

(a)This portion of the problem asks that we calculate, for a Pb-Mg alloy, the mass of lead in 7.5 kg of thesolidphase at 300C just below the solubility limit.From Figure 9.20, the solubility limit for thephase at

Explanation:

6 0

2 years ago

The monthly saving P that has to be deposit in a saving account that pays an annual interest rate of r in order to save a total

k0ka [10]

Answer:

Explanation:

for the first question:

P = F(r/12) (1 + r/12)^12N - 1

P = 10000(0.0435/12)(1+0.0435/12)^((12*N)-1)

n P

5 448.7710111

6 468.6865023

7 489.4858002

8 511.208126

9 533.894442

Using C#

public void Main( ){

Print(

}

public double CalcP(double T){

double a = 34172;

double b = 7.9622;

return Math.Exp(T/(0.0101*a) -b);

}

pubic void Print(params double[ ] T){

foreach (var t in T) {

Console.WriteLine( T-273 + " " + T + " " + CalcP(T) );

}

4 0

3 years ago