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insens350 [35]
3 years ago
13

A common process for increasing the moisture content of air is to bubble it through a column of water. The air bubbles are assum

ed to be spheres having an initial radius of 1.0 mm, and are in thermal equilibrium with the surrounding water. The saturation or equilibrium vapor pressure of water is temperature dependent, ranging from about 0.03 atm at 298 K to 1.0 atm at 373 K. The total pressure of the gas inside the air bubble is 1.0 atm, and will not change even as water evaporates into it. The bubbles initially contain some water vapor (along with the other components of air).
a. How will the final bubble radius vary i) with initial water vapor concentration in the bubble and ii) with bubble/water temperature?
b. Draw a picture of the physical system, and state at least five reasonable assumptions for the mass-transfer aspect of the water evaporation process. What coordinate system should be used?
c. What are the simplified differential forms of Fick's flux equation for water vapor (species A), the general differential equation for mass transfer in terms of concentration CA, and a resulting expression that combines the two (don't worry if it can't be too simplified).
d. Propose reasonable boundary and initial conditions

Engineering
1 answer:
likoan [24]3 years ago
5 0

Answer:

Explanation:

Assumptions is that

1. The flow is an unsteady one

2. Bubbles diameter is constant

3. The bubble velocity is slow

4. There is no homogenous reaction

5. It has a one dimensional flux model along the radial direction

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What fuel do rockets use
natta225 [31]

Liquid Hydrogen is the fuel used by rockets.

Explanation:

  • Liquid hydrogen which can be chemically denoted as "LH_{2}" is often considered as the significant fuels for rocket.
  • However rocket in its lower stages uses fuels such as Kerosene and oxygen where as in the higher stages such as second and third stages it uses liquid hydrogen.
  • Liquid hydrogen is known to easily cool the nozzle and then also other parts of the rocket before mixing with the oxidizer such as the oxygen.
  • Thus liquid hydrogen helps in preventing nozzle erosion and also reduces combustion chamber.
  • Liquid hydrogen one the other hand is very expensive as 384,071 gallons of it will cost approximately $376,389.58 .

Thus liquid hydrogen is effectively used as a fuel for rocket.

8 0
3 years ago
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A wastewater plant discharges a treated effluent (w) with a flow rate of 1.1 m^3/s, 50 mg/L BOD5 and 2 mg/L DO into a river (s)
4vir4ik [10]

A wastewater plant discharges a treated effluent (w) with a flow rate of 1.1 m^3/s, 50 mg/L BOD5 and 2 mg/L DO into a river (s) with a flow rate of 8.7 m^3/s, 6 mg/L BOD5 and 8.3 mg/L DO. Both streams are at 20°C. After mixing, the river is 3 meters deep and flowing at a velocity of 0.50 m/s. DOsat for this river is 9.0 mg/L. The deoxygenation constant is kd= 0.20 d^-1 and The reaction rate constant k at 20 °C is 0.27 d^-1.

The answer therefore would be the number 0.27 divided by two and then square while getting the square you would make it a binomial.

I wont give the answer but the steps

Your Welcome

8 0
3 years ago
Given below are the measured streamflows in cfs from a storm of 6-hour duration on a stream having a drainage area of 185 mi^2.
sertanlavr [38]

Answer:

33.56 ft^3/sec.in

Explanation:

Duration = 6 hours

drainage area = 185 mi^2

constant baseflow = 550 cfs

<u>Derive the unit hydrograph using the inverse procedure </u>

first step : calculate for the volume of direct runoff hydrograph using the details in table 2 attached below

Vdrh = sum of drh *  duration

        = 29700 * 6 hours ( 216000 secs )

        = 641,520,000 ft^3.

next step : Calculate the volume of runoff in equivalent depth

Vdrh / Area = 641,520,000  / 185 mi^2

                    = 1.49 in

Finally derive the unit hydrograph

Unit of hydrograph = drh /  volume of runoff in equivalent depth

                                = 50 ft^3 / 1.49 in  =  33.56 ft^3/sec.in

5 0
3 years ago
Determine whether or not each of the following four transaction execution histories is serializable. If a history is serializabl
ludmilkaskok [199]

Answer:

Option D. w1[x] w2[u] w2[y] w1[y] w3[x] w3[u] w1[z]

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The execution in the option D is correct. This is because there is more than one reasonable criterion.

8 0
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