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insens350 [35]
3 years ago
13

A common process for increasing the moisture content of air is to bubble it through a column of water. The air bubbles are assum

ed to be spheres having an initial radius of 1.0 mm, and are in thermal equilibrium with the surrounding water. The saturation or equilibrium vapor pressure of water is temperature dependent, ranging from about 0.03 atm at 298 K to 1.0 atm at 373 K. The total pressure of the gas inside the air bubble is 1.0 atm, and will not change even as water evaporates into it. The bubbles initially contain some water vapor (along with the other components of air).
a. How will the final bubble radius vary i) with initial water vapor concentration in the bubble and ii) with bubble/water temperature?
b. Draw a picture of the physical system, and state at least five reasonable assumptions for the mass-transfer aspect of the water evaporation process. What coordinate system should be used?
c. What are the simplified differential forms of Fick's flux equation for water vapor (species A), the general differential equation for mass transfer in terms of concentration CA, and a resulting expression that combines the two (don't worry if it can't be too simplified).
d. Propose reasonable boundary and initial conditions

Engineering
1 answer:
likoan [24]3 years ago
5 0

Answer:

Explanation:

Assumptions is that

1. The flow is an unsteady one

2. Bubbles diameter is constant

3. The bubble velocity is slow

4. There is no homogenous reaction

5. It has a one dimensional flux model along the radial direction

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We would like to measure the density (p) of an ideal gas. We know the ideal gas law provides p= , where P represents pressure, R
Nostrana [21]

Answer: =

Explanation:

=    P / (R * T) P- Pressure, R=287.058, T- temperature

From the given that

Sample mean(pressure) = 120300 Pa

Standard deviation (pressure) = 6600 Pa

Sample mean(temperature) = 340K

Standard deviation(temperature) = 8K

To calculate the Density;

Maximum pressure = Sample mean(pressure) + standard deviation (pressure) = 120300+6600 = 126900 Pa

Minimum pressure = Sample mean (pressure) - standard deviation (pressure)= 120300-6600 = 113700 Pa

Maximum temperature = Sample mean (temperature) + standard deviation (temperature) = 340+8 = 348K

Minimum temperature = Sample mean (temperature) - standerd deviation (temperature) = 340-8 = 332K

So now to calculate the density:

Maximum Density= Pressure (max)/(R*Temperature (min))= 126900/(287.058*332)= 1.331

Minimum density=Pressure(min)/(R*Temperature (max))= 113700/(287.058*348)= 1.138

Average density= (density (max)+ density (min))/2= (1.331+1.138)/2= 1.2345

cheers i hope this helps

5 0
3 years ago
If a 2 1/8 inch diameter medium carbon steel rod is to be turned between centers to a 2 inch diameter using high speed cutting b
Crank

Answer:

I think 1 31/32

8 0
4 years ago
A closed system consists of 0.3 kmol of octane occupying a volume of 5 m³. Determine (a) the weight of the system, in N, and (b)
Leni [432]

Answer:

a) m=336.18N

b) Vn=16.67m/kmol

Vm=0.1459m^3/kg

Explanation:

To calculate the mass of the octane(m):

Number of mole of octane (n) =0.3kmol(given)

Molarmass of octane (M) =114.23kg/kmol

m=n*M

m=(0.3kmol)*(114.23kg/kmol)

m=34.269kg

To calculate for the weight of octane(W):

W=g*m

W=(9.81m/s^2)*(34.269kg)

W=336.18N

b) For specific volumes of Vn and Vm:

Given volume of octane (V) =5m^3

Vm=V/m

Vm=5m^3/34.269kg

Vm=0.1459m^3/kg

And Vn will be :

Vn=V/m=5m^3/0.3kmol

Vn=16.67m/Kmol

Therefore, the answers are:

a) m=336.18N

b) Vn=16.67m/kmol

Vm=0.1459m^3/kg

7 0
3 years ago
If a weld is laying into a joint with a concave weld contour with undercutting issues, what might be the cause?
Katarina [22]

Answer:bbbb

Explanation:

4 0
3 years ago
Write a simple phonebook program that reads in a series of name-number pairs from the user (that is, name and number on one line
Vlad1618 [11]

Answer:

import java.util.HashMap;

import java.util.Map;

import java.util.Scanner;

public class PhoneBook {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       Map<String, String> map = new HashMap<>();

       String name, number, choice;

       do {

           System.out.print("Enter name: ");

           name = in.next();

           System.out.print("Enter number: ");

           number = in.next();

           map.put(name, number);

           System.out.print("Do you want to try again(y or n): ");

           choice = in.next();

       } while (!choice.equalsIgnoreCase("n"));

       System.out.print("Enter name to search for: ");

       name = in.next();

       if (map.containsKey(name)) {

           System.out.println(map.get(name));

       } else {

           System.out.println(name + " is not in the phone book");

       }

   }

}

6 0
3 years ago
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