Answer:
froce by 6 gallon liquid on moon surface is 2.86 lbf
Explanation:
given data:
at earth surface
volume of an incompressible liquid = Ve = 25 gallons
force by liquid = 70 lbf
on moon
volume of liquid = Vm = 6 gallons
gravitational acceleration on moon is am = 5.51 ft/s2
Due to incompressibility , the density remain constant.
mass of liquid on surface of earth

mass = 2.173 pound


froce by 6 gallon liquid on moon surface is
Fm = mass * acceleration
= density* volume * am
= 0.0869 *6* 5.51
= 2.86 lbf
Answer:
The greatest speedup possible with pipelining is 2.5 times
Explanation:
As we know
Span of stage = Maximum span of any span
As stage B has the maximum duration of time, So
Duration of time of each stage = Time duration of Stage B = 8 ns
Now calculate the total time without pipeline = Duration of Stage A + Duration of Stage B + Duration of Stage C + Duration of Stage D = 5 ns + 8 ns + 4 ns + 3 ns = 20 ns
So the greatest speedup can be calculated as follow
Greatest speedup = Total time without pipeline / Duration of time of each stage = 20 ns / 8 ns = 2.5 times
I don’t even know lol i’m just tryna bring my points up sorry.