The answer is B hope this helped
Assuming that it continues to accelerate at the same rate it will take another 10 seconds to reach 40 m/s.
Answer:
Explanation:
Since the first question states that there is a change in the velocity from rest to 20 m/s in 10 seconds time interval. So the acceleration experienced by the car during this 10 seconds should be determined first as follows:
Acceleration = (final velocity-initial velocity)/Time
Acceleration = (20-0)/10 = 2 m/s².
So this means the car is traveling with an acceleration of 2 m/s².
As it is stated that the car continues to move with same acceleration, then in the second case, the acceleration is fixed as 2 m/s², initial velocity as 20 m/s and final velocity as 40 m/s. So the time taken for the car to reach this velocity with the constant acceleration value will be as follows:
Time = Change in velocity/Acceleration
Time = (40-20)/2 = 20/2=10 s
So again in another 10 seconds by the car to reach 40 m/s from 20 m/s. Similarly the car will take a total of 20 seconds to reach from rest to 40 m/s value for velocity.
Would would have moved a total distance of 2k, because walking is a slower speed does not change distance
Answer:
There you have it. The y-component of air resistance for the fired bullet still depends on the fired speed of the bullet (since it is proportional to v2). A fired bullet (with air resistance) does not hit the ground at the same time as a dropped bullet.
Explanation:
hope this helped ✨
