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Margarita [4]
3 years ago
12

Why are we unlikely to find earth-like planets around halo stars in the galaxy? why are we unlikely to find earth-like planets a

round halo stars in th?
Physics
1 answer:
charle [14.2K]3 years ago
5 0
Halo stars are found in the space region of the Segmentum Obscurus. These stars are some of the oldest in the galaxy. However, they are situated in an environment where only very few elements are naturally occurring. Hence, most planets found there are rocky and are not suitable for habitable life.
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Which is an example of potential en
SIZIF [17.4K]

a yoyo in someones hand is an example of potential energy

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3 years ago
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Calculate the momentum of a 1800 kg elephant charging a hunter at a speed of 7.50 m/s.
liq [111]

The amount of movement, linear momentum, momentum or momentum is a physical quantity derived from a vector type that describes the movement of a body in any mechanical theory. In classical mechanics, the amount of movement is defined as the product of body mass and its velocity at a given time.

p= mv

Where,

m = mass

v = Velocity

Our values are given as,

m = 1800kg

v = 7.5m/s

Replacing we have that,

p = (1800)(7.5)

p = 13500kg\cdot m/s

Therefore the momentum is 13500kg\cdot m/s

8 0
3 years ago
What pulls all objects in the universe, including the moon and earth and the su
Salsk061 [2.6K]
It's called gravity, it attract the sun toward the gravitational pull making everything circulate. I don't really know how to explain it though.
6 0
3 years ago
A bus contains a 1440 kg flywheel (a disk that has a 0.63 m radius) and has a total mass of 10200 kg. Calculate the angular velo
CaHeK987 [17]

Answer:\omega =93.51 rad/s

Explanation:

Given

mass of Flywheel m_1=1440 kg

mass of bus m_b=10200 kg

radius of Flywheel r=0.63 m

final speed of bus v=21 m/s

Conserving Energy i.e.

0.9(Rotational Energy of Flywheel)= change in Kinetic Energy of bus

Let \omegabe the angular velocity of Flywheel

0.9\cdot \frac{I\omega ^2}{2}=\frac{m_bv^2}{2}

I=moment\ of\ Inertia =mr^2=1440\cdot 0.63^2=571.536 kg-m^2

0.9\cdot \frac{571.536\cdot \omega ^2}{2}=\frac{10200\cdot 21^2}{2}

\omega ^2=21^2\times \frac{10200}{0.9\times 571.536}

\omega =21\times 4.45=93.51 rad/s

8 0
3 years ago
A city bus travels 6 blocks east and 8 blocks north. Each block is 100 m long. If the bus travels this distance in 15 minutes, w
Eddi Din [679]

Answer:

1.56 m/s

Explanation:

For East direction, the 6 blocks is equivalent to 6*100=600 m

For West direction, 8 blocks is equivalent to 8*100=800 m

Speed is given by s=d/t where s is speed, d is distance covered and t is time taken

Total distance is 600+800=1400m

Time taken is 15 mins, converted to seconds will be 15*60=900 s

Speed, s=1400/900=1.5555555555555 m/s rounded off as 1.56 m/s

4 0
2 years ago
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