Question

In each cycle of a Carnot engine, 104 J of heat is absorbed from the high-temperature reservoir and 51 J is exhausted to the lowtemperature reservoir. What is the efficiency of the engine?

Answer 1

Answer:

the efficiency of the Carnot engine is e=0 .5060 (50.96%)

Explanation:

The carnot cycle effifiency e is calculated through

e = W/Q₂

where

W= work

Q₂= heat absorbed

Q₁= heat exhausted

from an energy balance

W= Q₂ - Q₁ ( the proportion of the heat absorbed that was not released was converted to work)

therefore

e=(Q₂-Q₁)/Q₂ = 1 - Q₁/Q₂ = 1 - 51 J/104 J = 0.5060 (50.96%)