Answer:
Explanation:
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In this case, we use the equation regarding the first law of thermodynamics which is:
In this case, the want to compute the change in thermal energy of the gas which is related with ΔU. In such a way, since the 10 J are being removed, they are set as negative in the aforesaid equation, moreover, the 40 J of work are positive since it is a work done on the system. Hence:
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Answer:Van der Waals forces are responsible for certain cases of pressure broadening (van der Waals broadening) of spectral lines and the formation of van der Waals molecules. ... The main characteristics of van der Waals forces are: They are weaker than normal covalent and ionic bonds.
Explanation:
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Answer:
1.24 L of H₂ at STP .
Explanation:
2Al(s) +6HCl(aq) → 2AlCl₃(aq) + 3H₂(g)
2 moles 3 x 22.4 L
2 x 27 g of Al reacts to give 3 x 22.4 L of H₂ at STP .
1 g of Al will react to give 3 x 22.4 / ( 2 x 27 ) L of H₂ at STP .
= 1.24 L of H₂ at STP .
Boron would have the lower first ionization energy.
Be: 1s2 2s2
B: 1s2 2s2 2p1 -> electron from the p orbital is easier to eject than than electron from the s orbital.