Answer:
the area is 10 feet by 10 feet, 100 feet²
subtract the area of the circle from this.
you get it by A = r² * pi
so 5² * 3.14159...
=78.5398163397
100-78.5398163397
is roughly 21.46 square feet
A^2=b^2+c^2-2bc Cos(A)
(270)^2=(255)^2+(442.85)^2-2(255)(442.85)Cos(A)
A=Cos^(-1)(270^2-255^2_(442.85)^2)/(-2*255*442.85)=33.5435
solve for angle A approximately is 33.54 degrees.
sinA/a=SinB/b
Sin33.54/270=SinB/255
B=Sin^(-1)(sin33.54/270*255)approximately is 31.45.
180-31.45-33.54=115.01 is Angle C.
Answer:
5/12
Step-by-step explanation:
You want the tangent of angle F in right triangle FGH with sides FG=24, GH=10, and FH=26.
<h3>Tangent</h3>
The mnemonic SOH CAH TOA is intended to remind you of the relations between trig functions and the sides of a right triangle. The TOA part of this tells you ...
Tangent = Opposite/Adjacent
<h3>Application</h3>
The side opposite angle F is GH = 10.
The side adjacent to angle F is FG = 24.
Then the tangent is ...
tan(F) = GH/FG = 10/24
tan(F) = 5/12 . . . . . reduced to lowest terms
Surface area of a cube is n^2, n being the measurment of any one side of the cube. In this case, 13x13=169, so the answer is 169 mL^2.
