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DanielleElmas [232]
2 years ago
13

How do chemists solve problems?

Chemistry
1 answer:
Westkost [7]2 years ago
4 0

Answer:Chemistry problems can be solved using a variety of techniques.

Explanation:  Many chemistry teachers and most introductory chemistry texts illustrate problem solutions using the factor-label method. ... The use of analogies and schematic diagrams results in higher achievement on problems involving moles, stoichiometry, and molarity. Hope this helped!

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W
DerKrebs [107]

Answer:

F = 30 N

Explanation:

Given data:

Mass of toy train = 1.5 kg

Acceleration of train = 20 m/s²

Amount of force acting on it = ?

Solution:

The net force on object is equal to the its mass multiply by its acceleration.

Formula:

F = ma

F = force

m = mass

a = acceleration

Now we will put the values in formula.

F = 1.5 kg × 20ms⁻²

F = 30 kg.ms⁻²

kg.ms⁻² = N

F = 30 N

7 0
2 years ago
In an exothermic reaction, energy is blank the surroundings.
S_A_V [24]

Answer: released to; absorbed from

- In an exothermic reaction, energy is released to the surroundings.

- In an endothermic reaction, energy is absorbed from the surroundings.

Explanation:

An exothermic reaction is a chemical reaction that occurs spontaneously and brings about the release of energy to the surroundings. Hence, the reacting vessel feels hot as the reaction proceeds.

An endothermic reaction, on the other hand, does not occur spontaneously and proceed only when energy is absorbed from the surroundings. Hence, the reacting vessel feels cold as the reaction proceeds.

5 0
2 years ago
Read 2 more answers
How many molecules are in 5.50 grams of AgNO3?
mixas84 [53]

Answer:

1.95*10²² molecules are in 5.50 grams of AgNO₃

Explanation:

Being the molar mass of the elements:

  • Ag: 107.87 g/mole
  • N: 14 g/mole
  • O: 16 g/mole

then the molar mass of the compound is:

AgNO₃: 107.87 g/mole + 14 g/mole + 3*16 g/mole= 169.87 g/mole

Then you can apply the following rule of three: if 169.87 grams of the compound are present in 1 mole, 5.50 grams will be present in how many moles?

moles=\frac{5.50 grams*1 mole}{169.87 grams}

moles= 0.0324

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number applies to any substance.

You can apply the following rule of three: if by definition of Avogadro's Number 1 mole of the substance contains 6.023 * 10²³ molecules, 0.0324 moles how many molecules will it have?

molecules=\frac{0.0324 moles*6.023*10^{23} molecules}{1 mole}

molecules=1.95*10²²

<u><em>1.95*10²² molecules are in 5.50 grams of AgNO₃</em></u>

3 0
2 years ago
Please help me im so lost! ​
Georgia [21]

Answer:

An atom consists of a positively charged nucleus, surrounded by one or more negatively charged particles called electrons. The positive charges equal the negative charges, so the atom has no overall charge; it is electrically neutral. ... The nucleus of an atom contains protons and neutrons.

Explanation:

i'm smart you are too in your own way.

5 0
3 years ago
In 1773 Benjamin Franklin, investigating the calming effect of oil on the water of a pond near London, observed that a teaspoonf
likoan [24]

Answer:

a. 2.44 nm

b. 15.33 nm²

Explanation:

a. Calculate the thickness (in nm) of the surface film

Since the volume of a teaspoon equals V = 4.93 cm³ and the area of the oil film is half an acre = 1/2 × 4046.86 m² = 2023.43 m²

The volume of the oil film, V' equals the volume of the oil in the teaspoon, V

V' = Ah where A = cross-sectional area of oil film = 2023.43 m² = 2023.43 × 10⁴ cm² and h = height of oil film

So, V' = V

Ah = V

h = V/A

= 4.93 cm³/2023.43 × 10⁴ cm²

= 0.00244 × 10⁻⁴ cm

= 2.44 × 10⁻⁷ cm

=  2.44 × 10⁻⁷ cm × 1m/100 cm

= 2.44 × 10⁻⁹ m

= 2.44 nm

b. The surface area (in nm2) occupied by an oleic acid molecule on water.

Since the height of the oil film equals the diameter of the oil molecule, and the molecule is assumed to be a sphere of radius, r. Its surface area is thus A = 4πr²

r = h/2 = 2.44 nm/2 = 1.22 nm

A = 4πr²

A = 4π(1.22 nm)²

A = 4.88π nm²

A = 15.33 nm²

7 0
2 years ago
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