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DanielleElmas [232]
3 years ago
13

How do chemists solve problems?

Chemistry
1 answer:
Westkost [7]3 years ago
4 0

Answer:Chemistry problems can be solved using a variety of techniques.

Explanation:  Many chemistry teachers and most introductory chemistry texts illustrate problem solutions using the factor-label method. ... The use of analogies and schematic diagrams results in higher achievement on problems involving moles, stoichiometry, and molarity. Hope this helped!

You might be interested in
If the reaction of 150. G of ammonia with 150. G of oxygen gas yields 87. G of nitric oxide (no), what is the percent yield of t
Gekata [30.6K]

The percentage yield of the given reaction is 77.33%.

What is percentage yield?
Reactants
frequently produce fewer product quantities than predicted by the chemical reaction's formula. The percentage of a theoretical yield that's been produced in a reaction is calculated using the percent yield formula. Working through a stoichiometry problem yields the theoretical yield, which is the ideal quantity of the final product. The actual yield is determined by calculating the volume of the product formed. We can determine the percentage yield by dividing the actual yield by the theoretical yield.

Moles is calculated by using the formula:
Moles of Ammonia:
Given mass of ammonia = 150g
Molar mass of ammonia = 17 g/mol
Putting values in above equation, we get:

Moles of Oxygen
Given mass of oxygen = 150g
Molar mass of oxygen = 32 g/mol
Putting values in above equation, we get:
For the given chemical equation:

By Stoichiometry,
5 moles of oxygen reacts with 4 moles of ammonia.
So, 4.6875 moles of oxygen will react with =  of ammonia
As, moles of ammonia required is less than the calculated moles. Hence, ammonia is present in excess and is termed as excess reagent.
Therefore, oxygen is considered as a limiting reagent because it limits the formation of products.

By Stoichiometry of the given reaction:
5 moles of oxygen gas produces 4 moles of nitric oxide
So, 4.6875 moles of oxygen gas will produce =  of nitric oxide

Now, to calculate the theoretical amount of nitric oxide, we use equation 1: Molar mass of nitric oxide = 30 g/mol
 Given mass of nitric oxide = 112.5 g
Now, to calculate the percentage yield, we use the formula:
Experimental yield = 87 g
Theoretical yield = 112.5 g
Putting values in above equation, we get:
Hence, the percentage yield of the given reaction is 77.33%.

learn more about percentage yield
brainly.com/question/14714924
#SPJ4

6 0
1 year ago
TIMED TEST PLS HELP (will give BRAINLIEST) According to some scientists, which is a cause of global warming? PICK ONLY ONE A) de
artcher [175]
I think its c maybe im not sure
7 0
2 years ago
Read 2 more answers
Which of the following best explains the trend in ionization energy across a period?
Alina [70]

A) It decreases because the distance between the nucleus and outermost shell increases

4 0
3 years ago
Read 2 more answers
The progress of the reaction:
Blababa [14]

Answer:

The Equilibrium constant K is far greater than 1; K>>1

Explanation:

The equilibrium constant, K, for any given reaction at equilibrium, is defined as the ratio of the concentration of the products raised to their stoichiometric coefficients divided by the concentration of reactants raised to their stoichiometric coefficients.

It tells us more about how how bigger or smaller the concentration of products is to that of the reactants when a reaction attains equilibrium. From the given data, as the color of the reactant mixture (Br2 is reddish-brown, and H2 is colourless) fades, more of the colorless product (HBr is colorless) is being formed as the reaction approaches equilibrium. This indicates yhat the concentration of products becomes relatively higher than that of the reactants as the reaction progresses towards equilibrium, the equilibrium constant K, must be greater than 1 therefore.

6 0
3 years ago
I need help with Chemistry: Mole Conversion<br> It must be answered in complete detail
Anni [7]

Answer:

As Per Given Information

Number of moles SO₂ ( Sulphur dioxide ) is 0.30

We 've been asked to find the number of atoms in given moles of Sulphur dioxide .

Value of Avogadro Number is 6.022 × 10²³ mol⁻¹

For finding the number of atoms we will use formale

\underline{\boxed{\textbf{\textsf{ Number \: of \: atoms \:  = Given \: moles \:  . Avogadro \: number}}}}

Putting the given value we obtain

\sf \twoheadrightarrow \: Number \: of \: atoms \:  = 0.30 \times 6.022 \times  {10}^{  23}    \\  \\ \sf \twoheadrightarrow \: Number \: of \: atoms \:  = \: 1.8066 \times  {10}^{ 23} atoms

So, the number of atoms in sulphur dioxide is 1.8066 × 10²³

8 0
1 year ago
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