This question involves the concepts of thickness and length.
"40" gold atoms could stack on top of one another in the gold foil.
<h3>NO. OF GOLD ATOMS THAT CAN STACK</h3>
We will use the unitary method here to find out the no. of gold atoms that could stack on top of each other in the gold foil of thickness 1 x 10⁻⁷ m, when the side length of each cubic atom is 2.5 x 10⁻⁹ m.
Therefore,
- 2.5 x 10⁻⁹ m thick gold foil can stack = 1 gold atom
- 1 m thick gold foil can stack = gold atoms
- 1 x 10⁻⁷ m thick gold foil can stack = gold atoms
- 1 x 10⁻⁷ m thick gold foil can stack = 40 gold atoms
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Since the product of P·Vis constant along an isotherm, an expansion to twice the volume implies a pressure reduction to half the original pressure. I hope my answer has come to your help. God bless and have a nice day ahead!<span>
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Force = mass times acceleration
F = 21000 x 36.9 = 774900
Therefore, 774900N force is required.
Answer:
When the parachute opens, the air resistance increases. The skydiver slows down until a new, lower terminal velocity is reached.