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Dmitry_Shevchenko [17]
4 years ago
12

A girl and a boy are riding on a merry-go-round that is turning at a constant rate. The girl is near the outer edge, and the boy

is closer to the center. For a given elapsed time interval, which rider has greater angular displacement?
A. Both the girl and the boy have the same nonzero angular displacement.
B. Both the girl and the boy have zero angular displacement.
C. The boy has greater angular displacement.
D. The girl has greater angular displacement.
Physics
1 answer:
masha68 [24]4 years ago
4 0

Answer:

A. Both the girl and the boy have the same nonzero angular displacement.

Explanation:

Since girl and boy both are standing on the same merry go round so here we can say that boy and girl both will revolve with same angular speed as the speed of the merry go round

so the angular displacement is given as

\theta = \omega t

so here since both has same angular speed that is the speed of the disc so they both will turn by same angle in the same interval of time

So we have correct answer as

A. Both the girl and the boy have the same nonzero angular displacement.

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You are at the carnival with you your little brother and you decide to ride the bumper cars for fun. You each get in a different
Aliun [14]

Answer:

<em>a) The equation is </em>(m_{b}+m_{c} )u_{b} = (m_{y}+m_{c} )v_{y} +  (m_{b}+m_{c} )v_{b}

<em>b) Your velocity after collision is 2.64 m/s</em>

<em>c) The force you felt is 7392 N</em>

<em>d) you and your brother undergo an equal amount of acceleration</em>

<em></em>

Explanation:

Your mass m_{y} = 60 kg

your brother's mass m_{b} = 30 kg

mass of the car m_{c} = 80 kg

your initial speed u_{y} = 0 m/s (since you've not started moving yet)

your brother's initial velocity u_{b} = 3 m/s

your final speed v_{y} after collision = ?

your brother's final speed v_{b} after collision = ?

a) equations you need to use to figure out how fast you and your brother are moving after the collision is

(m_{y}+m_{c} )u_{y} + (m_{b}+m_{c} )u_{b} = (m_{y}+m_{c} )v_{y} +  (m_{b}+m_{c} )v_{b}

but u_{y} = 0 m/s

the equation reduces to

(m_{b}+m_{c} )u_{b} = (m_{y}+m_{c} )v_{y} +  (m_{b}+m_{c} )v_{b}

b) if your little brother reverses with velocity of 0.36 m/s it means

v_{b} = -0.36 m/s (the reverse means it travels in the opposite direction)

then, imputing values into the equation, we'll have

(m_{b}+m_{c} )u_{b} = (m_{y}+m_{c} )v_{y} +  (m_{b}+m_{c} )v_{b}

(30 + 80)3 = (60 + 80)v_{y} + (30 + 80)(-0.36)

330 = 140v_{y} - 39.6

369.6 = 140v_{y}

v_{y} = 369.6/140 = <em>2.64 m/s</em>

This means you will also reverse with a velocity of 2.64 m/s

c) your initial momentum = 0  since you started from rest

your final momentum = (total mass) x (final velocity)

==>  (60 + 80) x 2.64 = 369.6 kg-m/s

If the collision lasted for 0.05 s,

then force exerted on you = (change in momentum) ÷ (time collision lasted)

force on you = ( 369.6 - 0) ÷ 0.05 =<em> 7392 N</em>

<em></em>

d) you changed velocity from 0 m/s to 2.64 m/s in 0.05 s

your acceleration is (2.64 - 0)/0.05 = 52.8 m/s^2

your brother changed velocity from 3 m/s to 0.36 m/s in 0.05 s

his deceleration is (3 - 0.36)/0.05 = 52.8 m/s

<em>you and your brother undergo an equal amount of acceleration. This is because you gained the momentum your brother lost</em>

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7 0
3 years ago
A uniform electric field exists in the region between two oppositely charged plane parallel plates. A proton is released from re
valentinak56 [21]

Answer:

a) 17.33 V/m

b) 6308 m/s

Explanation:

We start by using equation of motion

s = ut + 1/2at², where

s = 1.2 cm = 0.012 m

u = 0 m/s

t = 3.8*10^-6 s, so that

0.012 = 0 * 3.8*10^-6 + 0.5 * a * (3.8*10^-6)²

0.012 = 0.5 * a * 1.444*10^-11

a = 0.012 / 7.22*10^-12

a = 1.66*10^9 m/s²

If we assume the electric field to be E, and we know that F =qE. Also, from Newton's law, we have F = ma. So that, ma = qE, and E = ma/q, where

E = electric field

m = mass of proton

a = acceleration

q = charge of proton

E = (1.67*10^-27 * 1.66*10^9) / 1.6*10^-19

E = 2.77*10^-18 / 1.6*10^-19

E = 17.33 V/m

Final speed of the proton can be gotten by using

v = u + at

v = 0 + 1.66*10^9 * 3.8*10^-6

v = 6308 m/s

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3 years ago
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Answer:

Explanation:

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3 years ago
The number of wavelengths that pass a given point/second is called
myrzilka [38]

Answer:

I believe the answer is frequency

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Explanation:

6 0
3 years ago
Two processes of plant reproduction are described below.
alex41 [277]

Answer:

Process 1

Explanation:

Bees help move the pollen from flower to flower

5 0
3 years ago
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