Neutrons keep the Protons "in check", meaning Protons hold a very strong repulsive positive charge. The Neutrons counteract the repulsive force within a small space to keep the Nucleus stable.
I hope this helps! :)
Answer:
Almost everything in our surroundings represent chemical change
Explanation:
●Rusting of iron in presence of moisture and oxygen.
●Burning of wood.
●Milk becoming curd.
●Formation of caramel from sugar by heating.
●Baking of cookies and cakes.
●Cooking any food.
●Acid-base reaction.
●Digestion of food.
Answer:
G]ns^2np^5 group 17 (p-block)
G]ns^2np^2 group 14 (p-block)
G]ns^2mf^14 group 16 (f-block)
Explanation:
The outermost electronic configuration of an element shows the group to which it belongs in the periodic table as shown above in the answer. In addition, to that, we can be able to know from its electronic configuration, whether the element is a metal or not.
For instance;
G]ns^2mf^14 is a rare earth metal, G]ns^2np^2 group 14 is a metalloid while G]ns^2np^5 group 17 is a nonmetal.
Answer:

Explanation:
The I₂ is the common substance in the two equations.
(1) IO₃⁻ + 5I⁻ + 6H⁺ ⟶ 3I₂ + 3H₂O
{2) I₂ + 2S₂O₃²⁻ ⟶ 2I⁻ + S₄O₆²⁻
From Equation (1), the molar ratio of iodate to iodine is

From Equation (2), the molar ratio of iodine to thiosulfate is

Combining the two ratios, we get
