Al is 1.
As for NO3,it is one entity, an the whole thing is being multiplied by 3. Use the distributive property from math.
N is 3.
And O is 9.
In total, there are 13 atoms.
Answer:
it is pathogens i think its that
Explanation:
Answer : The energy required to melt 58.3 g of solid n-butane is, 4.66 kJ
Explanation :
First we have to calculate the moles of n-butane.
![\text{Moles of n-butane}=\frac{\text{Mass of n-butane}}{\text{Molar mass of n-butane}}](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20n-butane%7D%3D%5Cfrac%7B%5Ctext%7BMass%20of%20n-butane%7D%7D%7B%5Ctext%7BMolar%20mass%20of%20n-butane%7D%7D)
Given:
Molar mass of n-butane = 58.12 g/mole
Mass of n-butane = 58.3 g
Now put all the given values in the above expression, we get:
![\text{Moles of n-butane}=\frac{58.3g}{58.12g/mol}=1.00mol](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20n-butane%7D%3D%5Cfrac%7B58.3g%7D%7B58.12g%2Fmol%7D%3D1.00mol)
Now we have to calculate the energy required.
![Q=\frac{\Delta H}{n}](https://tex.z-dn.net/?f=Q%3D%5Cfrac%7B%5CDelta%20H%7D%7Bn%7D)
where,
Q = energy required
= enthalpy of fusion of solid n-butane = 4.66 kJ/mol
n = moles = 1.00 mol
Now put all the given values in the above expression, we get:
![Q=\frac{4.66kJ/mol}{1.00mol}=4.66kJ](https://tex.z-dn.net/?f=Q%3D%5Cfrac%7B4.66kJ%2Fmol%7D%7B1.00mol%7D%3D4.66kJ)
Thus, the energy required to melt 58.3 g of solid n-butane is, 4.66 kJ
<span>Acetonitrile molecules are mainly used in lithium batteries as a solvent, and is commonly found in the air from vehicle exhaust.
The geometry on</span><span> how two acetonitrile molecules would interact with each other is as follows:
_______
------- C======== N
The carbon atom has a single bond to the atom on its left side while having a triple bond on the nitrogen atom on the right side.
</span>